{"id":134242,"date":"2017-07-05T14:32:15","date_gmt":"2017-07-05T07:32:15","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=134242"},"modified":"2022-02-21T23:50:40","modified_gmt":"2022-02-21T16:50:40","slug":"listrik-dinamis-kelas-9-beserta-soal-dan-pembahasan-lengkap","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/fisika-un-sma\/listrik-dinamis-kelas-9-beserta-soal-dan-pembahasan-lengkap\/","title":{"rendered":"Listrik Dinamis Kelas 9 Beserta Soal dan Pembahasan Lengkap!"},"content":{"rendered":"

\"Listrik <\/a><\/p>\n

Hai Quipperian! Bagi kamu anak Kelas 9 SMP, pasti banyak mengalami kesulitan pada materi Fisika. Nah, Fisika di sini tentang Listrik Dinamis, nah kamu akan menemukan jalan keluarnya! Di artikel ini, Listrik Dinamis akan terasa mudah, lho! Karena ada beberapa contoh soal dan jawabannya!<\/span>
\n<\/span>
\n<\/span>Yuk mulai belajar!<\/span><\/p>\n

Soal Listrik Dinamis #1<\/b><\/h2>\n

Jika arus 4 ampere mengalir dalam kawat yang ujung-ujungnya mempunyai beda potensial 12 volt, maka besar muatan per menit yang mengalir melalui kawat sama dengan ..<\/span>
\n<\/span>a. 4 C \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 120 C<\/span>
\n<\/span>b. 12 C \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 240 C<\/span>
\n<\/span>c. 60 C<\/span>
\n<\/span>
\n<\/span>Jawaban: E<\/b><\/p>\n

Anak SMP dan Masih Sulit dengan Fisika? Ini Contoh Soal Listrik Dinamis Kelas 9 Lengkap dengan Pembahasannya!<\/a><\/h3>\n

Soal Listrik Dinamis #2<\/b><\/h2>\n

Jika dalam suatu penghantar mengalir muatan listrik sebesar 6 x 10\u20132 C selama 30 s, maka kuat arus listrik yang mengalir dalam penghantar itu adalah..<\/span>
\n<\/span>a. 2 mA \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 80 mA<\/span>
\n<\/span>b. 15 mA \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 120 mA<\/span>
\n<\/span>c. 30 mA<\/span>
\n<\/span><\/p>\n

Jawaban: a. 2 x 10\u20133 ampere = 2mA<\/b><\/p>\n

Soal Listrik Dinamis #3<\/b><\/h2>\n

Seutas kawat penghantar mempunyai panjang 50 cm, luas penampang 2 mm2, ternyata hambatan listriknya 100 ohm. Dengan demikian hambatan jenis kawat itu sebesar<\/span>
\n<\/span>a. 5 x 10 \u2013 6 ohm.m \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 5 x 10 \u2013 2 ohm.m <\/span>
\n<\/span>b. 2 x 10 \u2013 5 ohm.m \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 8 x 10 2 ohm.m<\/span>
\n<\/span>c. 4 x 10 \u2013 4 ohm.m
\n<\/span>
\n<\/span>Jawaban: c. 4 x 10\u2013 4 ohm.m<\/b><\/p>\n

Soal Listrik Dinamis #4<\/b><\/h2>\n

Tiga buah resistor masing-masing besarnya 3 ohm, 4 ohm, dan 6 ohm dihubungkan paralel, lalu kedua ujungnya dihubungkan ke sebuah bateray yang gglnya 8 volt dan hambatan dalamnya 2\/3 ohm. Tegangan jepit rangkaian adalah . . . .<\/span>
\n<\/span>a. 2,67 volt \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 8,00 volt<\/span>
\n<\/span>b. 5,33 volt \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 52,00 volt<\/span>
\n<\/span>c. 7,61 volt<\/span>
\n<\/span><\/p>\n

Jawaban: c. <\/b><\/p>\n

Rtotal = 3 + 4 + 6 + 0,67 = 13,67 ohm ; I = V\/R = 8\/13,67 = 0,59 A<\/span>
\n<\/span>Vjepit = I .Rjepit ; <\/span>
\n<\/span>Vjepit = 0,59 .( 3 + 4 + 6 ) = 7,61 volt<\/span><\/p>\n

Soal Listrik Dinamis #5<\/b><\/h2>\n

Untuk memperbesar hambatan suatu penghantar dapat dilakukan dengan cara <\/span>
\n<\/span>a. memperbesar beda potensial<\/span>
\n<\/span>b. memperbesar arusnya<\/span>
\n<\/span>c. memperbesar luas penampang<\/span>
\n<\/span>d. memperpanjang kawat<\/span>
\n<\/span>e. memperkecil beda potensialnya<\/span><\/p>\n

Jawaban: a<\/b><\/p>\n

Soal Listrik Dinamis #6<\/b><\/h2>\n

Faktor yang turut menentukan besar hambatan suatu kawat logam adalah <\/span>
\n<\/span><\/p>\n

1.panjang kawat<\/span>
\n<\/span>2.suhu kawat<\/span>
\n<\/span>3.luas penampang kawat<\/span>
\n<\/span>4.jenis bahan kawat<\/span>
\n<\/span><\/p>\n

Pernyataan yang benar adalah . . . .<\/span>
\na. 1, 2, dan 3 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 4 saja
\n<\/span>b. 1 dan 3 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. semua benar <\/span>
\n<\/span>c. 2 dan 4<\/span>
\n<\/span><\/p>\n

Jawaban: e<\/b>
\n<\/b><\/p>\n

Kapan Harusnya Kamu Memulai Les Privat Fisika?<\/a><\/h3>\n

Soal Listrik Dinamis #7<\/b><\/h2>\n

Sebuah kawat penghantar yang di hubungkan dengan bateray 6 volt mengalirkan arus listrik 0,5 Ampere. Jika kawat dipotong menjadi dua bagian sama panjang dan dihubungkan paralel satu sama lain ke bateray, maka arus yang mengalir sekarang adalah . . . <\/span><\/p>\n

a. 0,25 Ampere \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 6 Ampere
\nb. 0,5 Ampere \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 12 Ampere<\/span>
\n<\/span>c. 2,0 Ampere<\/span>
\n<\/span><\/p>\n

Jawaban: d<\/b><\/p>\n

Soal Listrik Dinamis #8<\/b><\/h2>\n

Sebuah lampu listrik tertulis 100 W \/ 220 V, agar lampu menyala dengan daya 25 watt, maka lampu itu harus dihubungkan dengan sumber tegangan listrik . . . .
\n<\/span>
\na. 100 volt \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 140 volt
\n<\/span>b. 110 volt \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 160 volt<\/span>
\n<\/span>c. 125 volt<\/span><\/p>\n

Jawaban: b<\/b><\/p>\n

Soal Listrik Dinamis #9<\/b><\/h2>\n

Suatu pemanas listrik memiliki hambatan 25 ohm dihubungkan dengan sumber tegangan 250 volt dan bekerja selama 24 jam, maka:
\n<\/span>
\n<\/span>1.arus yang mengalir dalam pemanas 10 ampere<\/span>
\n<\/span>2.daya pemanas sebesar 2,5 kWatt<\/span>
\n<\/span>3.jika tarif listrik Rp. 50,00\/kWh, selama waktu tersebut diperlukan biaya Rp. 300,00.
\n<\/span>
\n<\/span>Pernyataan yang benar adalah….
\na. 1\u00a0<\/span>\u00a0dan 2 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. hanya 1<\/span>
\n<\/span>b. 1 dan 3 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0e. 1, 2 dan 3<\/span>
\n<\/span>c. 2 dan 3<\/span><\/p>\n

Jawaban: a<\/b><\/p>\n

1). I = V\/R = 250\/25 = 10 A<\/span>
\n<\/span>2). P = V.I ; P = 250.10 = 2500 Watt = 2,5 kWatt<\/span>
\n<\/span>3). Biaya = 2,5 x 24 x Rp50,00 = Rp3.000,00<\/span><\/p>\n

Tiga buah hambatan 6 ohm, 4 ohm dan 12 ohm dipasang paralel dan dihubungkan dengan tegangan listrik. Perbandingan arus yang mengalir pada masing-masing hambatan adalah ….<\/span>
\n<\/span>a. 1 : 2 : 3 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0d. 6 : 3 : 2<\/span>
\n<\/span>b. 2 : 3 : 1 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0e. 6 : 2 : 3<\/span>
\n<\/span>c. 3 : 2 : 6<\/span><\/p>\n

Jawaban: b <\/b><\/p>\n

Rangkaian paralel V sama, sehingga : <\/span>
\n<\/span>V1 = V2 = V3<\/span>
\n<\/span>I1.6 = I2.4 = I3.12<\/span>
\n<\/span>I1 : I2 : I3 = 2 : 3 : 1<\/span><\/p>\n

Penulis: Sritopia<\/b><\/p>\n","protected":false},"excerpt":{"rendered":"

Hai Quipperian! Bagi kamu anak Kelas 9 SMP, pasti banyak mengalami kesulitan pada materi Fisika. Nah, Fisika di sini tentang Listrik Dinamis, nah kamu…<\/p>\n","protected":false},"author":156446345,"featured_media":134252,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[677999187],"tags":[],"ppma_author":[679386822],"class_list":["post-134242","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-fisika-un-sma"],"acf":[],"yoast_head":"\nListrik Dinamis Kelas 9 Beserta Soal dan Pembahasan Lengkap!<\/title>\n<meta name=\"description\" content=\"Quipperian, Materi Listrik Dinamis Kelas 9 wajib banget kalian pelajari agar pemahamanmu di pelajaran Fisika bisa makin mantap!\" \/>\n<meta name=\"robots\" content=\"index, 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