{"id":16142,"date":"2016-01-25T14:36:17","date_gmt":"2016-01-25T07:36:17","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=16142"},"modified":"2016-01-25T14:36:17","modified_gmt":"2016-01-25T07:36:17","slug":"catat-kisi-kisi-soal-sbmptn-kimia","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/masuk-ptn\/sbmptn\/kimia-sbmptn\/catat-kisi-kisi-soal-sbmptn-kimia\/","title":{"rendered":"Catat! Kisi-kisi Soal SBMPTN Kimia!"},"content":{"rendered":"<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207.jpg\" data-rel=\"penci-gallery-image-content\" ><img fetchpriority=\"high\" decoding=\"async\" class=\"size-full wp-image-16152\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207.jpg\" alt=\"Kisi-kisi Soal SBMPTN Kimia! \" width=\"800\" height=\"533\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207.jpg 800w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207-768x512.jpg 768w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207-585x390.jpg?crop=1 585w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/01\/02a35-rsz_photo_23432_20130207-263x175.jpg?crop=1 263w\" sizes=\"(max-width: 800px) 100vw, 800px\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Halo Quipperian, setelah selesai Ujian Nasional 2016, kamu bisa langsung mempersiapkan SBMPTN 2016. Bagi\u00a0kamu yang nantinya memilih jurusan kuliah di bidang IPA, maka kamu harus siap menghadapi ujian TPA, Matematika Dasar, Bahasa Indonesia, Bahasa Inggris, dan IPA yang meliputi Biologi, Kimia, dan Fisika.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Kali ini, kamu akan mendapat informasi tentang kisi-kisi soal SBMPTN Kimia. Kisi-kisi ini berfungsi agar proses belajarmu lebih fokus kepada materi yang memang akan diujikan di SBMPTN, Quipperian. Berikut ini adalah kisi-kisi soal SBMPTN Kimia beserta contoh soalnya, catat dan pelajari yaa.<\/span><\/p>\n<h2><b>Kisi-Kisi SBMPTN Kimia<\/b><\/h2>\n<ol>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Struktur Atom<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Sistem Periodik Unsur<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Ikatan Kimia<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Asam Basa Bronsted-Lowry<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0pH Asam Basa<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Titrasi Asam Basa<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Larutan Penyangga<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Hidrolisis Garam<\/span><\/li>\n<li><span style=\"font-weight:400;\"> \u00a0\u00a0\u00a0Tetapan Hasil Kali Kelarutan (Ksp)<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Reaksi Redoks<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Sel Volta<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Sel Elektrolisis<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Hukum Dasar Kimia (Hukum Proust)<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Persamaan Reaksi dan Konsep Mol<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Hitungan Kimia<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Sifat Koligatif<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Koloid<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Kimia Unsur<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Tata Nama Senyawa Karbon dan Isomer<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Reaksi-reaksi Senyawa Karbon<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Identifikasi Senyawa Karbon<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Benzena dan Turunannya<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Termokimia<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Laju Reaksi<\/span><\/li>\n<li><span style=\"font-weight:400;\">\u00a0 \u00a0Kesetimbangan Kimia<\/span><\/li>\n<\/ol>\n<h3 class=\"mh-loop-title\" style=\"text-align:center;\"><a href=\"https:\/\/video.quipper.com\/id\/blog\/mending-mana-pilih-pts-atau-ptn-setelah-lulus-sma\/\" rel=\"bookmark\">Mending Mana? Pilih PTS atau PTN Setelah Lulus SMA?<\/a><\/h3>\n<h2><b>Contoh Soal SBMPTN Kimia<\/b><\/h2>\n<p><strong><i>\u00a01. Gula 0.1 mol, nabium klorida 0,1 mol, dan natrium sulfat 0,1 mol masing-masing dilarutkan dalam 1 liter air (p air 1 g\/mL). Jika penurunan titik beku larutan gula adalah t<\/i><i>o<\/i><i>C, maka penurunan titik beku larutan natrium klorida dan natrium sulfat barturut-turut adalah&#8230;.<\/i><\/strong><\/p>\n<p><span style=\"font-weight:400;\">(A) t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C untuk kedua larutan<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B) t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">Cdan 2t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) 2t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C untuk kedua larutan<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) 2t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C dan 3t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) 3t<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">C untuk kedua larutan<\/span><\/p>\n<p><i style=\"line-height:1.5;\">\u00a0<strong>2. Jika 27,2 gram KH<\/strong><\/i><strong><i style=\"line-height:1.5;\">2<\/i><i style=\"line-height:1.5;\">PO<\/i><i style=\"line-height:1.5;\">4<\/i><\/strong><i style=\"line-height:1.5;\"><strong> (Mr =136) dilarutkan ke dalam 500 mL air, pH larutan yang terjadi adalah<\/strong>&#8230;.<\/i><\/p>\n<p><span style=\"font-weight:400;\">(diketahui Ka<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\">H<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\">PO<\/span><span style=\"font-weight:400;\">4<\/span><span style=\"font-weight:400;\"> =10<\/span><span style=\"font-weight:400;\">-3<\/span><span style=\"font-weight:400;\">, Ka<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">H<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\">PO<\/span><span style=\"font-weight:400;\">4<\/span><span style=\"font-weight:400;\"> =10<\/span><span style=\"font-weight:400;\">-8<\/span><span style=\"font-weight:400;\">, Ka<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\">H<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\">PO<\/span><span style=\"font-weight:400;\">4<\/span><span style=\"font-weight:400;\"> =10<\/span><span style=\"font-weight:400;\">-13<\/span><span style=\"font-weight:400;\">)<\/span><\/p>\n<p><span style=\"font-weight:400;\">(A) 8 +log2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B) 8,5 &#8211; log 2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) 7-log 2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) 4,5 +log 2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) 4,5 -log 2<\/span><\/p>\n<p><i style=\"line-height:1.5;\">\u00a0<strong>3. Senyawa 2-bromopropana dipanaskan dengan NaOH pekat akan menghasilkan senyawa golongan.<\/strong>&#8230;<\/i><\/p>\n<p><span style=\"font-weight:400;\">(A) Alkena<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B) Alkanal<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) Aldehid<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) Alkanoat<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) Alkana<\/span><\/p>\n<p><i style=\"line-height:1.5;\">\u00a0<strong>4. Gas metana (CH4, Mr 16) sebanyak 64 gram dapat bereaksl dengan gas Cl<\/strong><\/i><strong><i style=\"line-height:1.5;\">2<\/i><i style=\"line-height:1.5;\"> berlebih, menghasilkan 50,5 gram gas CH<\/i><i style=\"line-height:1.5;\">3<\/i><i style=\"line-height:1.5;\">Cl (Mr 50,5), 170 gram gas CH<\/i><i style=\"line-height:1.5;\">2<\/i><i style=\"line-height:1.5;\">Cl<\/i><i style=\"line-height:1.5;\">2<\/i><i style=\"line-height:1.5;\"> (Mr 85) dan X gram gas CHCl<\/i><i style=\"line-height:1.5;\">3<\/i><i style=\"line-height:1.5;\"> (Mr 120). Selelah dihitung dengan cermat dan teliti, rnaka massa gas CHCl<\/i><i style=\"line-height:1.5;\">3<\/i><\/strong><i style=\"line-height:1.5;\"><strong> adalah<\/strong>\u2026<\/i><\/p>\n<p><span style=\"font-weight:400;\">(A) 6 gram<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B) 12 gram<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) 30 gram<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) 60 gram<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) 120 gram<\/span><\/p>\n<p><i><span style=\"font-weight:400;\"><strong>\u00a05. Diketahui atom X memiliki 16 proton. Menurut kaidah oktet, molekul-molekul yang dapat dibentuk dengan 5Y adalah<\/strong>&#8230;.<\/span><\/i><\/p>\n<p><span style=\"font-weight:400;\">(A) XY<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> dan XY<\/span><span style=\"font-weight:400;\">3<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B) XY dan XY<\/span><span style=\"font-weight:400;\">2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) X<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">Ydan XY<\/span><span style=\"font-weight:400;\">3<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) hanya XY<\/span><span style=\"font-weight:400;\">2<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) hanya XY<\/span><span style=\"font-weight:400;\">3<\/span><\/p>\n<p><strong><i>\u00a06. Volume gas H<\/i><i>2<\/i><i> dan CI<\/i><i>2<\/i><i> yang dihasilkan pada elektrolisis akan sama jika digunakan muatan Iistrik yang sama<\/i><\/strong><\/p>\n<p><i><span style=\"font-weight:400;\">SEBAB:<\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">Jumlah eleklron yang lerlibal pada elektrolisis pembentukan gas H<\/span><\/i><i><span style=\"font-weight:400;\">2<\/span><\/i><i><span style=\"font-weight:400;\"> dan Cl<\/span><\/i><i><span style=\"font-weight:400;\">2<\/span><\/i><i><span style=\"font-weight:400;\"> sama.<\/span><\/i><\/p>\n<p><span style=\"font-weight:400;\">(A)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan benar, alasan benar dan menunjukkan hubungan sebab akibat<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan benar, alasan benar, tidak menunjukkan hubungan sebab akibat<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) <\/span><span style=\"font-weight:400;\">Pernyataan benar dan alasan salah<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) <\/span><span style=\"font-weight:400;\">Pernyataan salah dan alasan benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) \u00a0Pernyataan dan alasan, kedua-duanya salah<\/span><\/p>\n<p><i><span style=\"font-weight:400;\"><strong>7. Kelarutan besi (II) sulfida (FeS) dalam air dapat ditingkatkan dengan menambahkan HCL<\/strong><\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">SEBAB<\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">Ion S<\/span><\/i><i><span style=\"font-weight:400;\">2-<\/span><\/i><i><span style=\"font-weight:400;\"> akan bereaksi dengan H<\/span><\/i><i><span style=\"font-weight:400;\">+<\/span><\/i><i><span style=\"font-weight:400;\"> membentuk gas H<\/span><\/i><i><span style=\"font-weight:400;\">2<\/span><\/i><i><span style=\"font-weight:400;\">S<\/span><\/i><\/p>\n<p><span style=\"font-weight:400;\">(A)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan benar, alasan benar dan menunjukkan hubungan sebab akibat<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan benar, alasan benar, tidak menunjukkan hubungan sebab akibat<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan benar dan alasan salah<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D)\u00a0<\/span><span style=\"font-weight:400;\">Pernyataan salah dan alasan benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) Pernyataan dan alasan, kedua-duanya salah<\/span><\/p>\n<p><i><span style=\"font-weight:400;\">\u00a0<strong>8. Padatan NaCI melebur pada 801<\/strong><\/span><\/i><strong><i>o<\/i><i>C sedangkan padatan CCI<\/i><i>4<\/i><i> me\/abur pada 23<\/i><i>o<\/i><i>C. pernyataan yang dapal menjelaskan perbedaan titik lebur kedua padatan adalah\u2026 (Ar Na=23, CI =35,5, C=12)<\/i><\/strong><\/p>\n<p><i><span style=\"font-weight:400;\">(1) NaCI mudah larut di dalam air<\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">(2) Mr NaCl leblh besar dari Mr CCl<\/span><\/i><i><span style=\"font-weight:400;\">4<\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">(3) NaCI merupakan elektrolit kuat<\/span><\/i><\/p>\n<p><i><span style=\"font-weight:400;\">(4) Interaksi kisi kristal dalam padatan NaCI lebih kuat<\/span><\/i><\/p>\n<p>Manakah yang benar?<\/p>\n<p><span style=\"font-weight:400;\">(A)\u00a0<\/span><span style=\"font-weight:400;\">Jika (1), (2), dan (3) benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(B)\u00a0<\/span><span style=\"font-weight:400;\">Jika (1) dan (3) benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(C) <\/span><span style=\"font-weight:400;\">Jika (2) dan (4) benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(D) <\/span><span style=\"font-weight:400;\">Jika hanya (4) saja yang benar<\/span><\/p>\n<p><span style=\"font-weight:400;\">(E) <\/span><span style=\"font-weight:400;\">Jika semua jawaban benar<\/span><\/p>\n<hr \/>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight:400;\">Semoga kisi-kisi SBMPTN Kimia dan contoh soalnya dapat memberikan gambaran padamu seperti apa nantinya soal tes SBMPTN 2016. Semoga bermanfaat dan selamat belajar ya Quipperian!<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Halo Quipperian, setelah selesai Ujian Nasional 2016, kamu bisa langsung mempersiapkan SBMPTN 2016. Bagi\u00a0kamu yang nantinya memilih jurusan kuliah di bidang IPA, maka kamu&hellip;<\/p>\n","protected":false},"author":156446345,"featured_media":16152,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[549090506],"tags":[],"ppma_author":[679386822],"class_list":["post-16142","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimia-sbmptn"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Catat! 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