{"id":16432,"date":"2016-02-02T11:09:09","date_gmt":"2016-02-02T04:09:09","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=16432"},"modified":"2016-02-02T11:09:09","modified_gmt":"2016-02-02T04:09:09","slug":"simak-pembahasan-soal-matematika-dasar-sbmptn","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/masuk-ptn\/sbmptn\/matematika-sbmptn\/simak-pembahasan-soal-matematika-dasar-sbmptn\/","title":{"rendered":"Simak Pembahasan Soal Matematika Dasar SBMPTN"},"content":{"rendered":"<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533.jpg\" data-rel=\"penci-gallery-image-content\" ><img fetchpriority=\"high\" decoding=\"async\" class=\"size-full wp-image-17072 aligncenter\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533.jpg\" alt=\"Pembahasan Soal Matematika Dasar SBMPTN\" width=\"799\" height=\"533\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533.jpg 799w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533-768x512.jpg 768w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533-585x390.jpg?crop=1 585w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/432a7-shutterstock_60140344_799x533-263x175.jpg?crop=1 263w\" sizes=\"(max-width: 799px) 100vw, 799px\" \/><\/a><\/p>\n<p>Bagi kamu yang akan mengikuti tes SBMPTN, apapun pilihan bidangmu, baik IPA maupun IPS, kamu pasti akan diuji TKPA yang berisi ujian TPA, Matematika Dasar, Bahasa Inggris dan Bahasa Indonesia. Maka dari itu, penting sekali untuk dapat mengerjakan TKPA dengan baik. Nah, untuk menunjang proses belajarmu, kamu bisa belajar pembahasan soal-soal Matematika Dasar yang akan disajikan berikut ini. Simak baik-baik yaa.<\/p>\n<p><i><span style=\"font-weight:400;\">\u00a0<strong>1. Jika <\/strong><\/span><\/i><strong><i>p<\/i><i>log a = 2 dan <\/i><i>q<\/i><i>log 8p = 2, maka <\/i><i>2p<\/i><i>log pq<\/i><i>2<\/i><i>\/a =<\/i><\/strong><\/p>\n<p><span style=\"font-weight:400;\">a.\u00a03 <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">log2p<\/span><\/p>\n<p><span style=\"font-weight:400;\">b.\u00a02<\/span><span style=\"font-weight:400;\">log 2p<\/span><\/p>\n<p><span style=\"font-weight:400;\">c.\u00a03\/ <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">log 2p:<\/span><\/p>\n<p><span style=\"font-weight:400;\">d.\u00a01\u00a0\/<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">log 2p<\/span><\/p>\n<p><span style=\"font-weight:400;\">e.\u00a03\/ <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">log p<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawabannya<\/span><b> C<\/b><\/p>\n<p><span style=\"font-weight:400;\">Pembahasan:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Perhatikan bentuk lain logaritma berikut<\/span><\/p>\n<p><span style=\"font-weight:400;\">p<\/span><span style=\"font-weight:400;\">log a = 2 <\/span><span style=\"font-weight:400;\">\u00e0<\/span><span style=\"font-weight:400;\"> a = p<\/span><span style=\"font-weight:400;\">2<\/span><\/p>\n<p><span style=\"font-weight:400;\">q<\/span><span style=\"font-weight:400;\">log 8p = 2 <\/span><span style=\"font-weight:400;\">\u00e0<\/span><span style=\"font-weight:400;\"> 8p = q<\/span><span style=\"font-weight:400;\">2<\/span> <span style=\"font-weight:400;\">\u00e0<\/span><span style=\"font-weight:400;\"> q<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> = 8p<\/span><\/p>\n<p><span style=\"font-weight:400;\">Kemudian dengan mensubstitusi a dan q2 diperoleh<\/span><\/p>\n<p><span style=\"font-weight:400;\">2p<\/span><span style=\"font-weight:400;\">log pq<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">\/a = <\/span><span style=\"font-weight:400;\">2p<\/span><span style=\"font-weight:400;\">log p.8p\/p<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> = <\/span><span style=\"font-weight:400;\">2p<\/span><span style=\"font-weight:400;\">log8 = <\/span><span style=\"font-weight:400;\">2p<\/span><span style=\"font-weight:400;\">log 2<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\"> = 3 <\/span><span style=\"font-weight:400;\">2p<\/span><span style=\"font-weight:400;\">log 2 = 3\/<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">log 2p<\/span><\/p>\n<p><i style=\"font-size:16px;\">\u00a0<strong>2. Jika 2a + 1 &lt; 0 dan grafik y = x<\/strong><\/i><strong><i style=\"font-size:16px;\">2<\/i><i style=\"font-size:16px;\"> \u2013 4ax + a bersinggungan dengan grafik y = 2x<\/i><i style=\"font-size:16px;\">2<\/i><i style=\"font-size:16px;\"> + 2x, maka a<\/i><i style=\"font-size:16px;\">2<\/i><i style=\"font-size:16px;\"> + 1 = \u2026<\/i><\/strong><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/58201-images-1.jpg\" data-rel=\"penci-gallery-image-content\" ><img decoding=\"async\" class=\"alignnone wp-image-16952\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/58201-images-1.jpg\" alt=\"Images 1\" width=\"145\" height=\"169\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Jawabannya <\/span><b>C<\/b><\/p>\n<p><span style=\"font-weight:400;\">Pembahasan:<\/span><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/dd8dc-rumus.jpg\" data-rel=\"penci-gallery-image-content\" ><img decoding=\"async\" class=\"alignnone wp-image-17002\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/dd8dc-rumus.jpg\" alt=\"rumus\" width=\"355\" height=\"34\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Kedua bersinggungan, maka determinan dari f(x) = y<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2013 y<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> sama dengan nol.<\/span><\/p>\n<p><span style=\"font-weight:400;\">y<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> = y<\/span><span style=\"font-weight:400;\">1<\/span><\/p>\n<p><span style=\"font-weight:400;\">2x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> + 2x = x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2013 4ax + a<\/span><\/p>\n<p><span style=\"font-weight:400;\">x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> + (2 + 4a)x \u2013 a = 0<\/span><\/p>\n<p><span style=\"font-weight:400;\">Sehingga A = 1, B = 2 + 4a, C = -a<\/span><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/892e2-rumus-3.jpg\" data-rel=\"penci-gallery-image-content\" ><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-17012\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/892e2-rumus-3.jpg\" alt=\"rumus 3\" width=\"421\" height=\"242\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Sehingga a2 + 1 = (-1)<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> + 1 = 1 + 1 = 2<\/span><\/p>\n<h3 class=\"mh-loop-title\" style=\"text-align:center;\"><a href=\"https:\/\/video.quipper.com\/id\/blog\/4-hal-wajib-untuk-persiapan-satu-bulan-sebelum-sbmptn\/\" rel=\"bookmark\">4 Hal Wajib untuk Persiapan Satu Bulan Sebelum SBMPTN<\/a><\/h3>\n<p><i><span style=\"font-weight:400;\">\u00a0<strong>3. Jika titik (x,y) memenuhi x<\/strong><\/span><\/i><strong><i>2<\/i><i> \u2264 y \u2264 x + 6, maka nilai maksimum x+y adalah\u2026<\/i><\/strong><\/p>\n<p><span style=\"font-weight:400;\">a. 5<\/span><\/p>\n<p><span style=\"font-weight:400;\">b. 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">c. 7<\/span><\/p>\n<p><span style=\"font-weight:400;\">d. 9<\/span><\/p>\n<p><span style=\"font-weight:400;\">e. 12<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawabannya <\/span><b>E<\/b><\/p>\n<p><span style=\"font-weight:400;\">Pembahasan:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Perhatikan bahwa x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2264 y \u2264 x + 6, sehingga dapat ditulis:<\/span><\/p>\n<p><span style=\"font-weight:400;\">x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">\u2264 x + 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2013 x \u2013 6 \u2264 0<\/span><\/p>\n<p><span style=\"font-weight:400;\">(x + 2)(x \u2013 3) \u2264 0<\/span><\/p>\n<p><span style=\"font-weight:400;\">-2 \u2264 x \u2264 3<\/span><\/p>\n<p><span style=\"font-weight:400;\">Sehingga diperoleh bahwa nilai x akan ebrada pada interval tersebut dan maksimum nilai x adalah 3, kemudian perhatikan<\/span><\/p>\n<p><span style=\"font-weight:400;\">x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2264 y \u2264 x + 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">x + x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2264 x + y \u2264 x + x + 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">x + x<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> \u2264 x + y \u2264 2x + 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari pernyataan di atas diperoleh bahwa nilai maksimum dari x + y adalah 2x + 6, karena nilai maksimum x adalah 3, maka maksimum dari x + y adalah 2x + 6 = 2(3) + 6 = 12<\/span><\/p>\n<p><i><span style=\"font-weight:400;\">\u00a0<strong>4. Suku tengah suatu barisan aritmatika adalah 23. Jika suku terakhirnya 43 dan suku ketiganya 13, maka banyak suku barisan ini adalah\u2026<\/strong><\/span><\/i><\/p>\n<p><span style=\"font-weight:400;\">a. 5<\/span><\/p>\n<p><span style=\"font-weight:400;\">b. 7<\/span><\/p>\n<p><span style=\"font-weight:400;\">c. 9<\/span><\/p>\n<p><span style=\"font-weight:400;\">d. 11<\/span><\/p>\n<p><span style=\"font-weight:400;\">e. 13<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawabannya<\/span><b> C<\/b><\/p>\n<p><span style=\"font-weight:400;\">Pembahasan:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari soal diperoleh<\/span><\/p>\n<p><span style=\"font-weight:400;\">U<\/span><span style=\"font-weight:400;\">T<\/span><span style=\"font-weight:400;\"> = 23<\/span><\/p>\n<p><span style=\"font-weight:400;\">Un = 43<\/span><\/p>\n<p><span style=\"font-weight:400;\">U<\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\"> = 13<\/span><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/b733d-rumus-4.jpg\" data-rel=\"penci-gallery-image-content\" ><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-17022\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/b733d-rumus-4.jpg\" alt=\"rumus 4\" width=\"339\" height=\"215\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Dengan menggunakan rumus Un diperoleh:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Un = U<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> + (n \u2013 1)b<\/span><\/p>\n<p><span style=\"font-weight:400;\">43 = 3 + (n \u2013 1)5<\/span><\/p>\n<p><span style=\"font-weight:400;\">43 = 3 + 5n \u2013 5<\/span><\/p>\n<p><span style=\"font-weight:400;\">5n = 45<\/span><\/p>\n<p><span style=\"font-weight:400;\">n = 9<\/span><\/p>\n<p><span style=\"font-weight:400;\">Maka banyak sukunya adalah 9<\/span><\/p>\n<p><i><span style=\"font-weight:400;\">\u00a0<strong>5. SMA X memiliki 6 kelas dengan banyak siswa pada setiap kelas adalah 16 pria dan 16 wanita. Jika untuk kepengurusan OSIS dipilih satu orang dari setiap kelas, maka peluang 2 orang wanita yang menjadi pengurus OSIS adalah\u2026<\/strong><\/span><\/i><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/02651-rumus-5.jpg\" data-rel=\"penci-gallery-image-content\" ><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-17032\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/02651-rumus-5.jpg\" alt=\"rumus 5\" width=\"107\" height=\"217\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Jawabannya <\/span><b>B<\/b><\/p>\n<p><span style=\"font-weight:400;\">Pembahasan:<\/span><\/p>\n<p><span style=\"font-weight:400;\">n(s) = <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> x <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> x <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> x <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> x <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> x <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">C<\/span><span style=\"font-weight:400;\">1<\/span><span style=\"font-weight:400;\"> = 2 x 2 x 2 x 2 x 2 x 2 = 64<\/span><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/033f4-rumus-6.jpg\" data-rel=\"penci-gallery-image-content\" ><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-17042\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/033f4-rumus-6.jpg\" alt=\"rumus 6\" width=\"347\" height=\"79\" \/><\/a><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/0f642-rumus-70.jpg\" data-rel=\"penci-gallery-image-content\" ><img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-17062\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/02\/0f642-rumus-70.jpg\" alt=\"rumus 70\" width=\"529\" height=\"267\" \/><\/a><\/p>\n<p><span style=\"font-weight:400;\">Substitusi x = 0 ke persamaan di atas, diperoleh:<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -3. (2f(0) \u2013 1)<\/span><span style=\"font-weight:400;\">-4<\/span><span style=\"font-weight:400;\">. 2f\u2019(0)<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -3. (2(1) \u2013 1)<\/span><span style=\"font-weight:400;\">-4<\/span><span style=\"font-weight:400;\">. 2(2)<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -3. (2\u2013 1)<\/span><span style=\"font-weight:400;\">-4<\/span><span style=\"font-weight:400;\">. 4<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -3. (1)<\/span><span style=\"font-weight:400;\">-4<\/span><span style=\"font-weight:400;\">. 4<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -3. 1. 4<\/span><\/p>\n<p><span style=\"font-weight:400;\">g\u2019(0) = -12<\/span><\/p>\n<hr \/>\n<p>&nbsp;<\/p>\n<p><span style=\"font-weight:400;\">Gimana Quipperian? Pembahasannya sudah cukup jelas kan? Soal-soal Matematika Dasar SBMPTN tidak sulit kan? Yuk, belajar lebih rajin lagi dan berlatih lebih banyak soal.<\/span><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Bagi kamu yang akan mengikuti tes SBMPTN, apapun pilihan bidangmu, baik IPA maupun IPS, kamu pasti akan diuji TKPA yang berisi ujian TPA, Matematika&hellip;<\/p>\n","protected":false},"author":156446345,"featured_media":17072,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_newsletter_access":"","_jetpack_dont_email_post_to_subs":false,"_jetpack_newsletter_tier_id":0,"_jetpack_memberships_contains_paywalled_content":false,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":"","jetpack_post_was_ever_published":false},"categories":[253044991],"tags":[],"ppma_author":[679386822],"class_list":["post-16432","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-matematika-sbmptn"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.8 - 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