{"id":23152,"date":"2016-03-15T12:09:19","date_gmt":"2016-03-15T05:09:19","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=23152"},"modified":"2021-11-24T21:25:16","modified_gmt":"2021-11-24T14:25:16","slug":"semua-yang-ada-di-luar-angkasa-berhubungan-dengan-fisika-yuk-belajar-contoh-soal-ujian-nasional-fisika-ini-biar-canggih","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/fisika-un-sma\/semua-yang-ada-di-luar-angkasa-berhubungan-dengan-fisika-yuk-belajar-contoh-soal-ujian-nasional-fisika-ini-biar-canggih\/","title":{"rendered":"Semua yang Ada di Luar Angkasa Berhubungan dengan Fisika, Yuk Belajar Contoh Soal Ujian Nasional Fisika Ini Biar Canggih!"},"content":{"rendered":"

\"Contoh<\/a><\/p>\n

Ini dia, salah satu mata pelajaran yang dianggap mengerikan oleh mayoritas murid kelas XII SMA jurusan IPA. Rasanya berat sekali untuk memulai belajar Fisika, ya, Quipperian? Tapi, jangan sampai kamu menunda-nundanya terus. UN sudah sebentar lagi, lho. Kamu tidak mau, kan, harus menghadapinya tanpa persiapan? Kamu bisa mengerjakan beberapa contoh soal di bawah ini. Quipper Video Blog sudah memilih yang sesuai dengan kisi-kisi dari Badan Standar Nasional Pendidikan (BSNP), kok.<\/span><\/p>\n

Pengukuran dan Kinematika<\/b><\/h2>\n

Sebuah batu dijatuhkan dari puncak menara yang tingginya 40 m di atas tanah. Jika percepatan gravitasi 10 m.s-2, maka perkiraan waktu yang diperlukan batu untuk sampai di tanah adalah\u2026.<\/span><\/p>\n

    \n
  1. 2,4 s<\/span><\/li>\n
  2. 2,6 s<\/span><\/li>\n
  3. 2,8 s<\/span><\/li>\n
  4. 3,0 s<\/span><\/li>\n
  5. 3,2 s<\/span><\/li>\n<\/ol>\n

    Pembahasan:<\/span><\/p>\n

    Benda bergerak jatuh bebas, sehingga:<\/span><\/p>\n

    t = <\/span><\/i>\u221a2h\/g = \u221a2 . 40 \/ 10 = \u221a80\/10 = \u221a8 = 2\u221a2 = 2 . (1,414) = 2,828s = 2,8 s<\/span><\/p>\n

    Jawaban: 3<\/b><\/p>\n

    Dinamika<\/b><\/h2>\n

    Sebuah balok dengan massa <\/span>m <\/span><\/i>dilepaskan dari puncak bidang licin dengan kemiringan <\/span>x. <\/span><\/i>Agar percepatan balok pada bidang miring sama dengan 70% percepatan gravitasinya, maka perkiraan nilai x yang tepat adalah\u2026.<\/span><\/p>\n

      \n
    1. 30<\/span>o<\/span><\/li>\n
    2. 37<\/span>o<\/span><\/li>\n
    3. 45<\/span>o<\/span><\/li>\n
    4. 53<\/span>o<\/span><\/li>\n
    5. 60<\/span>o<\/span><\/li>\n<\/ol>\n

      Pembahasan:<\/span><\/p>\n

      Gaya yang menarik benda meluncur dengan percepatan a = 0,7g di bidang miring adalah beratnya sendiri, yaitu <\/span>w<\/span><\/i>sin<\/span>x, <\/span><\/i>sehingga persamaannya:<\/span><\/p>\n

              \u03a3<\/span>F = <\/span><\/i>ma<\/span><\/p>\n

        w<\/span><\/i>sin<\/span>x = <\/span><\/i>ma<\/span><\/p>\n

      mg<\/span><\/i>sin<\/span>x<\/span><\/i> = m . (0,7 g)<\/span><\/p>\n

           sin<\/span>x = <\/span><\/i>0,7<\/span><\/p>\n

           sin<\/span>x <\/span><\/i>= \u00bd \u221a2<\/span><\/p>\n

                 <\/span>x <\/span><\/i>= 45<\/span>o<\/span><\/p>\n

      Jawaban: 3<\/b><\/p>\n

      Usaha dan Energi<\/b><\/h2>\n

      Sebuah benda bermassa 4 kg mula-mula diam, kemudian benda bergerak lurus dengan percepatan 3 m.s<\/span>-2<\/span>. Usaha yang diubah menjadi energi kinetic setelah 2 detik adalah\u2026.<\/span><\/p>\n

        \n
      1. 6 joule<\/span><\/li>\n
      2. 12 joule<\/span><\/li>\n
      3. 24 joule<\/span><\/li>\n
      4. 48 joule<\/span><\/li>\n
      5. 72 joule<\/span><\/li>\n<\/ol>\n

        Pembahasan:<\/span><\/p>\n

        v<\/span>t<\/span> = v<\/span>o<\/span> + at<\/span><\/p>\n

        = 0 + 3 . 2<\/span><\/p>\n

        = 6 m.s<\/span>-1<\/span><\/p>\n

        W<\/span> = \u0394<\/span>E<\/span><\/i>k<\/span><\/i><\/p>\n

        = E<\/span>k2<\/span> \u2013 E<\/span>k1<\/span><\/p>\n

        = \u00bd mv<\/span>2<\/span>2<\/span> \u2013 \u00bd mv<\/span>1<\/span>2<\/span><\/p>\n

        = \u00bd (4) . (6)<\/span>2<\/span> \u2013 \u00bd (4) . (0)<\/span>2<\/span><\/p>\n

        = 72 joule<\/span><\/p>\n

        Jawaban: 5<\/b><\/p>\n

        Kalor <\/b><\/h2>\n

        Pada proses termodinamika, pernyataan yang menunjukkan gas mengalami proses isobarik adalah jika\u2026.<\/span><\/p>\n

          \n
        1. Perubahan gas yang suhunya selalu tetap<\/span><\/li>\n
        2. Perubahan gas yang tekanannya selalu tetap<\/span><\/li>\n
        3. Kecepatan rata-rata partikel bertambah<\/span><\/li>\n
        4. Usaha luar gas sebanding dengan suhunya<\/span><\/li>\n
        5. Suhu dan volume gas tidak mengalami perubahan<\/span><\/li>\n<\/ol>\n

          Pembahasan:<\/span><\/p>\n

          Proses isobarik adalah proses termodinamika yang terjadi pada tekanan konstan.<\/span><\/p>\n

          Jawaban: 2<\/b><\/p>\n

          Gelombang dan Optik<\/b><\/h2>\n

          Taraf intensitas bunyi sebuah terompet yang terdengar pada jarak 5 m adalah 75 dB. Taraf intensitas bunyi seratus terompet yang terdengar pada jarak 50 m adalah\u2026.<\/span><\/p>\n

            \n
          1. 55 dB<\/span><\/li>\n
          2. 65 dB<\/span><\/li>\n
          3. 75 dB<\/span><\/li>\n
          4. 85 dB<\/span><\/li>\n
          5. 95 dB<\/span><\/li>\n<\/ol>\n

            Pembahasan:<\/span><\/p>\n

            Pada kondisi pertama, jumlah terompet <\/span>n1 <\/span><\/i>= 1 dan jarak terompet <\/span>r1 <\/span><\/i>= 5m menghasilkan taraf intensitas <\/span>TI1 = <\/span><\/i>75 dB<\/span>.<\/span><\/i><\/p>\n

            Pada kondisi kedua, jumlah terompet <\/span>n2 <\/span><\/i>= 100 dan jarak terompet <\/span>r2 <\/span><\/i>= 50 m.<\/span><\/p>\n

            Sehingga, taraf intensitas untuk perubahan jumlah dan jarak sumber bunyi adalah:<\/span><\/p>\n

            TI2<\/span><\/i> =<\/span> TI1 <\/span><\/i>+ 10 . log (<\/span>n2\/n1) <\/span><\/i>\u2013 20 . log (<\/span>r2\/r1<\/span><\/i>)<\/span><\/p>\n

            = 75 + 10 . log (100\/1) \u2013 20 . log (50\/5)<\/span><\/p>\n

            = 75 + 10 . log100 \u2013 20 . log10<\/span><\/p>\n

            = 75 + 10 . (2) \u2013 20 . (1)<\/span><\/p>\n

            = 75 +20 \u2013 2-<\/span><\/p>\n

            = 75 dB<\/span><\/p>\n

            Jawaban: 3<\/b><\/p>\n

            Listrik, Magnet, dan Fisika Modern<\/b><\/h2>\n

            Arus listrik mengalir sepanjang kawat listrik tegangan tinggi dari selatan ke utara. Arah induksi magnetik yang diakibatkan arus listrik di atas kawat tersebut adalah ke\u2026.<\/span><\/p>\n

              \n
            1. Utara<\/span><\/li>\n
            2. Timur<\/span><\/li>\n
            3. Selatan<\/span><\/li>\n
            4. Barat<\/span><\/li>\n
            5. Bawah<\/span><\/li>\n<\/ol>\n

              Pembahasan:<\/span><\/p>\n

              Arah induksi mangnetik ditentukan dengan aturan genggaman tangan kanan. Arah arus pada kawat lurus ditunjukkan oleh ibu jari, dan arah induksi magnetik ditentukan oleh arah putaran keempat jarin tangan yang dirapatkan. Kawat pada soal dapat diterangkan melalui penjelasan berikut:<\/span><\/p>\n

                \n
              • Arah mata angina mewakili arah sebenarnya, sehingga bagian atas kawat yaitu bagian depan kawat, dan bagian bawah kawat adalah bagian belakang kawat.<\/span><\/li>\n
              • Arus listrik mengalir di kawat dari selatan ke utara<\/span><\/li>\n
              • Arah induksi magnetik mewakili putaran genggaman tangan<\/span><\/li>\n<\/ul>\n

                Ditanyakan arah induksi magnetik di bagian atas kawat, maka kita harus melihat arah putaran tangan di bagian depan kawat. Maka, kesimpulannya, arah induksi magnetik pada bagian atas kawat adalah ke timur.<\/span><\/p>\n

                Jawaban: 2<\/b><\/p>\n

                \n

                 <\/p>\n

                Quipperian, semoga beberapa contoh soal di atas dapat membantu kamu dalam mengerjakan soal-soal UN Fisika 2016 nanti, ya. Mayoritas jenis soalnya memang merupakan hitung-hitungan, itulah mengapa kamu harus sering-sering mengerjakan soal-soal latihan. Jika masih ada yang belum dipahami, jangan segan untuk segera bertanya pada guru atau teman yang jago Fisika. Semangat!<\/span><\/p>\n

                 <\/p>\n","protected":false},"excerpt":{"rendered":"

                Ini dia, salah satu mata pelajaran yang dianggap mengerikan oleh mayoritas murid kelas XII SMA jurusan IPA. Rasanya berat sekali untuk memulai belajar Fisika,…<\/p>\n","protected":false},"author":156446345,"featured_media":23172,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[677999187],"tags":[],"ppma_author":[679386822],"class_list":["post-23152","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-fisika-un-sma"],"acf":[],"yoast_head":"\nBelajar Contoh Soal Ujian Nasional Fisika<\/title>\n<meta name=\"description\" content=\"Ini contoh soal dan kisi-kisi dari Badan Standar Nasional Pendidikan (BSNP)\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" 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