{"id":276507,"date":"2019-10-21T13:27:48","date_gmt":"2019-10-21T06:27:48","guid":{"rendered":"https:\/\/quipperhome.wpcomstaging.com\/?p=276507"},"modified":"2021-11-24T20:26:57","modified_gmt":"2021-11-24T13:26:57","slug":"kinematika-fisika-kelas-11-konsep-rumus-dan-contoh-soal","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/mapel\/fisika\/kinematika-fisika-kelas-11-konsep-rumus-dan-contoh-soal\/","title":{"rendered":"Kinematika Vektor &#8211; Fisika Kelas 11 &#8211; Konsep, Rumus, dan Contoh Soal"},"content":{"rendered":"<p><img fetchpriority=\"high\" decoding=\"async\" class=\"alignnone size-full wp-image-276565\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal.png\" alt=\"Kinematika - Fisika Kelas 11 - Konsep, Rumus, dan Contoh Soal\" width=\"800\" height=\"533\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal.png 800w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal-768x512.png 768w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal-585x390.png?crop=1 585w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal-263x175.png?crop=1 263w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-Konsep-Rumus-dan-Contoh-Soal-300x200.png 300w\" sizes=\"(max-width: 800px) 100vw, 800px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Halo Quipperian! Pada kesempatan kali ini Quipper Blog akan membahas suatu topik yang menarik lho, yaitu \u201c<\/span><i><span style=\"font-weight: 400;\">Solusi Super Menyelesaikan Soal tentang Kinematika Vektor<\/span><\/i><span style=\"font-weight: 400;\">\u201d. Tahukah kamu berdasarkan data yang Quipper Blog punya, topik soal tentang Kinematika Vektor adalah soal yang selalu keluar dalam SBMPTN Fisika lho. Jumlahnya kira-kira 8 soal tiap tahun. Namun ironinya, masih banyak siswa yang mengalami kesulitan dalam menjawab soal tentang ini. Hal ini bisa disebabkan karena masih kesulitannya siswa menggunakan konsep integral dan differensial pada fungsi kinematika.\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Penggunaan arah relatif terhadap produk kinematika (posisi, kecepatan, dan percepatan) yang selalu membuat bingung. Dalam penyelesaian gerak parabola siswa biasanya lupa menggunakan rumus untuk mengindentifikasi titik tertinggi atau titik terjauh serta waktu di tititik tertinggi atau titik terjauh. 10 topik Fisika yang paling sering muncul di SBMPTN ditunjukkan pada gambar 1. Segala kesulitan tersebut sebenarnya dapat diselesaikan menggunakan SOLUSI SUPER akan kinematika Vektor ini. Oleh sebab itu, pada sesi kali ini Quipper Blog akan membahas detail tentang :\u00a0<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Persamaan gerak dan analisis vektor<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Perpindahan, kecepatan, dan percepatan relatif<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Gerak parabola<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Soal dan Pembahasan menggunakan SOLUSI SUPER dari Bank Soal Quipper.<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400;\">Menarik, bukan? <\/span><i><span style=\"font-weight: 400;\">Check this Out<\/span><\/i><span style=\"font-weight: 400;\">!!<\/span><\/p>\n<p><img decoding=\"async\" class=\"alignnone size-full wp-image-276553\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-1.png\" alt=\"\" width=\"493\" height=\"412\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-1.png 493w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-1-300x251.png 300w\" sizes=\"(max-width: 493px) 100vw, 493px\" \/><\/p>\n<h2><b>Cara Menentukan Komponen Vektor<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Dalam analisis suatu vektor terdapat dua komponen utama yang harus kita ketahui yaitu, komponen <\/span><b>horizontal (sumbu x)<\/b><span style=\"font-weight: 400;\"> dan komponen <\/span><b>vertikal (sumbu y<\/b><span style=\"font-weight: 400;\">). kedua komponen vektor tersebut memiliki resultan yang memiliki besar dan arah. Nilai besar nya yaitu <\/span><b>akar dari jumlah kuadrat komponen x<\/b><span style=\"font-weight: 400;\"> dan<\/span><b> y<\/b><span style=\"font-weight: 400;\"> sedangkan arahnya adalah <\/span><b>tangen<\/b><span style=\"font-weight: 400;\"> dari komponen <\/span><b>vertikal<\/b><span style=\"font-weight: 400;\"> dibagi komponen <\/span><b>horizontal<\/b><span style=\"font-weight: 400;\">. Cara menentukan komponen-komponen vektor adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><img decoding=\"async\" class=\"alignnone size-full wp-image-276552\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-2.png\" alt=\"\" width=\"323\" height=\"278\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-2.png 323w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-2-300x258.png 300w\" sizes=\"(max-width: 323px) 100vw, 323px\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276551\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-3.png\" alt=\"\" width=\"568\" height=\"200\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-3.png 568w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-3-300x106.png 300w\" sizes=\"(max-width: 568px) 100vw, 568px\" \/><\/p>\n<h2><b>Posisi dan Perpindahan Partikel\u00a0<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Suatu benda memiliki posisi dan perpindahan. <\/span><b>Posisi<\/b><span style=\"font-weight: 400;\"> merupakan suatu besaran <\/span><b>skalar<\/b><span style=\"font-weight: 400;\"> sedangkan <\/span><b>perpindahan<\/b><span style=\"font-weight: 400;\"> adalah besaran <\/span><b>vektor<\/b><span style=\"font-weight: 400;\">. Perbedaaan keduanya adalah sebagai berikut :<\/span><b>\u00a0 Posisi ( r ) <\/b><span style=\"font-weight: 400;\">merupakan kedudukan benda terhadap titik acuan.<\/span> <span style=\"font-weight: 400;\">Posisi dapat dinyatakan dengan vektor-vektor satuan pada sumbu <\/span><b>x ditulis i<\/b><span style=\"font-weight: 400;\">, dan sumbu <\/span><b>y ditulis j<\/b><span style=\"font-weight: 400;\">. Persamaannya adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276550\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-4.png\" alt=\"\" width=\"431\" height=\"59\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-4.png 431w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-4-300x41.png 300w\" sizes=\"(max-width: 431px) 100vw, 431px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Sedangkan<\/span><b> Perpindahan (\u0394r)<\/b><span style=\"font-weight: 400;\"> adalah perubahan posisi benda dalam waktu tertentu. Perpindahan dapat dirumuskan sebagai berikut:\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276549\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-5.png\" alt=\"\" width=\"473\" height=\"126\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-5.png 473w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-5-300x80.png 300w\" sizes=\"(max-width: 473px) 100vw, 473px\" \/><br \/>\n<span style=\"font-weight: 400;\">Karena perpindahan merupakan besaran vektor, sehingga perpindahan mempunyai arah. Cara menentukan nilai <\/span><b>arah <\/b><span style=\"font-weight: 400;\">pada perpindahan adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276548\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-6.png\" alt=\"\" width=\"143\" height=\"79\" \/><\/p>\n<h2><b>Kecepatan Rata-rata dan Kecepatan Sesaat:\u00a0<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Suatu benda memiliki kecepatan rata-rata dan kecepatan sesaat. Perbedaanya adalah sebagai berikut : . <\/span><b>Kecepatan rata-rata <\/b><span style=\"font-weight: 400;\">v<\/span><span style=\"font-weight: 400;\"> adalah hasil bagi perpindahan dengan selang waktu yang diperlukan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276547\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-7.png\" alt=\"\" width=\"165\" height=\"77\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Kecepatan rata-rata partikel dalam bidang dapat juga dinyatakan secara vektor yaitu dalam komponen-komponennya terhadap sumbu-X dan sumbu- Y yakni :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276546\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-8.png\" alt=\"\" width=\"124\" height=\"47\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Sedangkan <\/span><b>kecepatan sesaat<\/b><span style=\"font-weight: 400;\"> merupakan <\/span><b>turunan pertama (differensial)<\/b><span style=\"font-weight: 400;\"> fungsi posisi yaitu :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276545\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-9.png\" alt=\"\" width=\"144\" height=\"77\" \/><\/p>\n<p><b>Integral suatu fungsi<\/b><\/p>\n<p><span style=\"font-weight: 400;\">Posisi partikel dapat ditentukan menggunakan integral dari fungsi kecepatan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276544\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-10-.png\" alt=\"\" width=\"158\" height=\"121\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-10-.png 158w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-10--80x60.png 80w\" sizes=\"(max-width: 158px) 100vw, 158px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Lalu dapat dicari resultannya yaitu :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276543\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-11.png\" alt=\"\" width=\"162\" height=\"71\" \/><\/p>\n<h2><b>Percepatan Partikel\u00a0\u00a0<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Hampir serupa dengan kecepatan rata-rata dan sesaat. Suatu benda memiliki percepatan rata-rata dan percepatan sesaat. Perbedaanya adalah sebagai berikut : <\/span><b>Percepatan rata-rata (a)<\/b><span style=\"font-weight: 400;\"> adalah perubahan kecepatan dalam waktu tertentu :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276542\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-12.png\" alt=\"\" width=\"516\" height=\"171\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-12.png 516w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-12-300x99.png 300w\" sizes=\"(max-width: 516px) 100vw, 516px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Dengan <\/span><b>arah percepatan<\/b><span style=\"font-weight: 400;\"> :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276541\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-13.png\" alt=\"\" width=\"149\" height=\"65\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Sedangkan <\/span><b>Percepatan sesaat<\/b><span style=\"font-weight: 400;\"> merupakan <\/span><b>turunan pertama dari fungsi kecepatan dan turunan kedua dari fungsi posisi<\/b><span style=\"font-weight: 400;\">. Nilainya adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276540\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-14.png\" alt=\"\" width=\"232\" height=\"70\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Kecepatan dapat ditentukan menggunakan integral dari fungsi percepatan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276539\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-15.png\" alt=\"\" width=\"203\" height=\"72\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Suatu fungsi dari kinematika (posisi, kecepatan, dan percepatan) memiliki suatu hubungan. Hubungannya dapat digambarkan pada gambar 2.\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276538\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-16.png\" alt=\"\" width=\"665\" height=\"450\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-16.png 665w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-16-300x203.png 300w\" sizes=\"(max-width: 665px) 100vw, 665px\" \/><\/p>\n<h2><b>Kecepatan Relatif<\/b><\/h2>\n<p><span style=\"font-weight: 400;\">Kecepatan suatu benda dapat bersifat relative artinya acuan terhadap pengukuran kecepatan harus dinyatakan dengan jelas. Untuk benda-benda yang berada di atas tanah, umumnya kecepatan benda ditetapkan terhadap acuan tanah (pengamat yang diam di tanah). Untuk benda-benda yang bergerak di permukaan air, umumnya kecepatan benda ditetapkan terhadap acuan arus air. Kecepatan relatif A terhadap B (ditulis Vab) adalah selisih antara kecepatan relatif A terhadap acuan bersama C (ditulis Vac) dengan kecepatan relatif B terhadap acuan bersama C (ditulis V bc). Rumus kecepatan relative dapat menjadi sebagai berikut :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276537\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-17.png\" alt=\"\" width=\"202\" height=\"49\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Hal yang sama berlaku bagi perpindahan dan percepatan. Untuk tiga acuan A, B, dan C berlaku :\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Perpindahan relatif :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276536\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-18.png\" alt=\"\" width=\"154\" height=\"73\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Percepatan relatif :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276535\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-19.png\" alt=\"\" width=\"220\" height=\"73\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Sebagai contoh ilustrasi gerak relatif adalah gerak yang terjadi pada arus sungai.\u00a0 sebuah perahu bergerak dengan kecepatan 25 m\/s. lalu perahu tersebut diombang-ambingkan dengan arus sungai yang bergerak dengan kecepatan 10 m\/s. Berapakah kecepatan perahu yang diamati oleh seorang pengamat di titik B. kecepatan perahu yang diamati oleh pengamat di titik B sama dengan V perahu ditambah V arus sungai yaitu<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276534\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-20.png\" alt=\"\" width=\"192\" height=\"83\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Ilustrasi di atas dapat ditunjukkan pada gambar 4.\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276533\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-21.png\" alt=\"\" width=\"625\" height=\"361\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-21.png 625w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-21-300x173.png 300w\" sizes=\"(max-width: 625px) 100vw, 625px\" \/><\/p>\n<h2><b>Gerak Parabola<\/b><\/h2>\n<p><b>Gerak parabola<\/b><span style=\"font-weight: 400;\"> adalah resultan perpindahan suatu benda yang serentak melakukan <\/span><b>gerak lurus beraturan pada arah horizontal<\/b><span style=\"font-weight: 400;\"> dan <\/span><b>gerak lurus berubah beraturan pada arah vertikal<\/b><span style=\"font-weight: 400;\">. Dalam menganalisis gerak parabola, kita dapat memandangnya sebagai dua gerak yang terpisah, yaitu <\/span><b>gerak lurus beraturan (GLB) pada sumbu-X<\/b><span style=\"font-weight: 400;\"> dan <\/span><b>gerak lurus berubah beraturan (GLBB) pada sumbu-Y<\/b><span style=\"font-weight: 400;\">. Tiap gerak ini tidak saling mempengauhi sehingga bola yang dijatuhkan bebas dan bola yang dilempar horizontal pada saat bersamaan akan jatuh di tanah pada saat yang bersamaan pula. Contoh gerak parabola dan komponen-komponenya ditunjukkan pada gambar 5. Dalam menganalisis gerak parabola kita membuat tiga asumsi berikut :\u00a0<\/span><\/p>\n<ol>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Percepatan jatuh bebas g memiliki besar yang tetap.<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Pengaruh hambatan udara atau gesekan udara diabaikan<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Rotasi bumi tidak mempengaruhi gerakan.\u00a0<\/span><\/li>\n<\/ol>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276532\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-22.png\" alt=\"\" width=\"638\" height=\"413\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-22.png 638w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-22-300x194.png 300w\" sizes=\"(max-width: 638px) 100vw, 638px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pada gambar 5 terdapat komponen-komponen yang terjadi pada gerak parabola yaitu persamaan kecepatan (<\/span><b>kecepatan horizontal dan kecepatan vertikal), waktu tertinggi, waktu terjauh, jarak terjauh, dan titik tertinggi<\/b><span style=\"font-weight: 400;\">. Rumus pada komponen-komponenya adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><span style=\"font-weight: 400;\">Rumus <\/span><b>kecepatan awal horizontal (Vox)<\/b><span style=\"font-weight: 400;\"> dan <\/span><b>kecepatan awal vertikal (Voy<\/b><span style=\"font-weight: 400;\">) yaitu :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276531\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-23.png\" alt=\"\" width=\"468\" height=\"67\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-23.png 468w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-23-300x43.png 300w\" sizes=\"(max-width: 468px) 100vw, 468px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Rumus <\/span><b>jarak terjauh (Xh)<\/b><span style=\"font-weight: 400;\"> dan <\/span><b>titik tertinggi (Yh)<\/b><span style=\"font-weight: 400;\"> adalah sebagai berikut :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276530\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-24.png\" alt=\"\" width=\"408\" height=\"86\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-24.png 408w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-24-300x63.png 300w\" sizes=\"(max-width: 408px) 100vw, 408px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Rumus Jarak Horizontal pada titik terjauh Xa\u00a0 sama dengan dua kali rumus jarak terjauh yaitu sebagai berikut :\u00a0\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276529\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-25.png\" alt=\"\" width=\"178\" height=\"75\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Waktu yang dibutuhkan untuk mencapai titik tertinggi :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276528\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-26.png\" alt=\"\" width=\"154\" height=\"75\" \/><\/p>\n<p><span style=\"font-weight: 400;\">dan Lama waktu terbang suatu benda (titik terakhir) adalah sebagai berikut :\u00a0\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276527\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-27.png\" alt=\"\" width=\"156\" height=\"69\" \/><\/p>\n<h2><b>Tips dan Trik SOLUSI SUPER dalam penyelesaian soal Kinematika Vektor<\/b><\/h2>\n<ol>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Dalam penyelesaian soal vektor, jangan lupa untuk memasukkan komponen waktu pada fungsinya. Lalu apabila ditanya besar resultan dari posisi atau perpindahan. Jangan lupa untuk mengakarkan dari kuardrat komponen horizontal dan komponen vertikal.\u00a0<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Dalam penyelesaian soal kecepatan sesaat atau kecepatan rata-rata. Kecepatan sesaat dapat diperoleh dari turunan pertama fungsi posisi sedangkan kecepatan rata-rata adalah besar perpindahan dibagi dengan waktu. Waktu yang dipakai adalah waktu akhir dikurangi waktu awal.\u00a0<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Dalam penyelesaian gerak parabola, selalu ingat persyaratan pada gerak parabola yaitu : untuk sumbu-X percepatan horizontal (a<sub style=\"font-family: -apple-system, BlinkMacSystemFont, 'Segoe UI', Roboto, Oxygen-Sans, Ubuntu, Cantarell, 'Helvetica Neue', sans-serif;\">x<\/sub><\/span><span style=\"font-weight: 400;\">=0<\/span><span style=\"font-weight: 400;\">) dan kecepatan horizontal serta kecepatan awal horizontal ( <\/span><span style=\"font-weight: 400;\">V<\/span><sub><span style=\"font-weight: 400;\">x<\/span><\/sub><span style=\"font-weight: 400;\">= <\/span><span style=\"font-weight: 400;\">V<\/span><sub><span style=\"font-weight: 400;\">ox<\/span><\/sub><span style=\"font-weight: 400;\"> = tetap). Sedangkan gerak parabola pada sumbu-Y percepatan vertikal ( <\/span><span style=\"font-weight: 400;\">a<\/span><sub><span style=\"font-weight: 400;\">y<\/span><\/sub><span style=\"font-weight: 400;\">= -g)<\/span><span style=\"font-weight: 400;\">. Pada titik tertinggi syarat yang dipenuhi adalah (<\/span><span style=\"font-weight: 400;\">V<\/span><sub><span style=\"font-weight: 400;\">h<\/span><\/sub><span style=\"font-weight: 400;\">=0)<\/span><span style=\"font-weight: 400;\">sedangkan untuk titik terjauh nilai <\/span><span style=\"font-weight: 400;\">y<\/span><sub><span style=\"font-weight: 400;\">a<\/span><\/sub><span style=\"font-weight: 400;\">=0<\/span><span style=\"font-weight: 400;\">.\u00a0<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight: 400;\">Di atas sudah dijelaskan tips dan trik SOLUSI SUPER dalam penyelesaian soal Kinematika Vektor. Sekarang waktunya melihat soal dan pembahasan dari bank soal Quipper yang selalu <\/span><i><span style=\"font-weight: 400;\">up to date<\/span><\/i><span style=\"font-weight: 400;\"> untuk persiapan Quipper menghadapi segala test yang ada<\/span><b>.\u00a0<\/b><\/p>\n<h2><b>Contoh Soal: Vektor Posisi<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276526\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-28.png\" alt=\"\" width=\"514\" height=\"132\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-28.png 514w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-28-300x77.png 300w\" sizes=\"(max-width: 514px) 100vw, 514px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276525\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-29.png\" alt=\"\" width=\"477\" height=\"264\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-29.png 477w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-29-300x166.png 300w\" sizes=\"(max-width: 477px) 100vw, 477px\" \/><\/p>\n<h2><b>Contoh Soal: Vektor Perpindahan<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276524\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-30.png\" alt=\"\" width=\"483\" height=\"164\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-30.png 483w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-30-300x102.png 300w\" sizes=\"(max-width: 483px) 100vw, 483px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276523\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-31.png\" alt=\"\" width=\"300\" height=\"406\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-31.png 300w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-31-222x300.png 222w\" sizes=\"(max-width: 300px) 100vw, 300px\" \/><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276522\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-32.png\" alt=\"\" width=\"332\" height=\"307\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-32.png 332w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-32-300x277.png 300w\" sizes=\"(max-width: 332px) 100vw, 332px\" \/><\/p>\n<h2><b>Contoh Soal: Kecepatan Rata-rata<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276561\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Screen-Shot-2019-10-21-at-13.17.21.png\" alt=\"\" width=\"489\" height=\"156\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Screen-Shot-2019-10-21-at-13.17.21.png 489w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Screen-Shot-2019-10-21-at-13.17.21-300x96.png 300w\" sizes=\"(max-width: 489px) 100vw, 489px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276521\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-33.png\" alt=\"\" width=\"345\" height=\"678\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-33.png 345w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-33-153x300.png 153w\" sizes=\"(max-width: 345px) 100vw, 345px\" \/><\/p>\n<h2><b>Contoh Soal: Kecepatan Sesaat<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276520\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-34.png\" alt=\"\" width=\"497\" height=\"143\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-34.png 497w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-34-300x86.png 300w\" sizes=\"(max-width: 497px) 100vw, 497px\" \/><br \/>\n<span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<h2><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276519\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-35.png\" alt=\"\" width=\"322\" height=\"288\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-35.png 322w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-35-300x268.png 300w\" sizes=\"(max-width: 322px) 100vw, 322px\" \/><\/h2>\n<h2><b>Contoh Soal: Gerak Parabola<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276518\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-36.png\" alt=\"\" width=\"508\" height=\"114\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-36.png 508w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-36-300x67.png 300w\" sizes=\"(max-width: 508px) 100vw, 508px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<h2><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276517\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-37.png\" alt=\"\" width=\"295\" height=\"271\" \/><\/h2>\n<h2><b>Contoh Soal: Kecepatan pada Gerak Parabola<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276516\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-38.png\" alt=\"\" width=\"463\" height=\"129\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-38.png 463w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-38-300x84.png 300w\" sizes=\"(max-width: 463px) 100vw, 463px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276515\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-39.png\" alt=\"\" width=\"299\" height=\"314\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-39.png 299w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-39-286x300.png 286w\" sizes=\"(max-width: 299px) 100vw, 299px\" \/><\/p>\n<h2><b>Contoh Soal: Komponen Kecepatan pada Gerak Parabola<\/b><\/h2>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276514\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-40.png\" alt=\"\" width=\"494\" height=\"157\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-40.png 494w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-40-300x95.png 300w\" sizes=\"(max-width: 494px) 100vw, 494px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<h2><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276513\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-41.png\" alt=\"\" width=\"358\" height=\"362\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-41.png 358w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-41-297x300.png 297w\" sizes=\"(max-width: 358px) 100vw, 358px\" \/><br \/>\n<b>Contoh Soal: Waktu Terjauh pada Gerak Parabola<\/b><\/h2>\n<p><span style=\"font-weight: 400;\"> <img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276512\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-42.png\" alt=\"\" width=\"497\" height=\"143\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-42.png 497w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-42-300x86.png 300w\" sizes=\"(max-width: 497px) 100vw, 497px\" \/><\/span><\/p>\n<p><span style=\"font-weight: 400;\">Pembahasan :\u00a0<\/span><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-276511\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-43.png\" alt=\"\" width=\"379\" height=\"357\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-43.png 379w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2019\/10\/Kinematika-Fisika-Kelas-11-43-300x283.png 300w\" sizes=\"(max-width: 379px) 100vw, 379px\" \/><\/p>\n<p><span style=\"font-weight: 400;\">Bagaimana Quipperian sudah mulai memahami cara penyelesaian soal kinematika vektor menggunakan SOLUSI SUPER Quipper. Ternyata dengan memahami konsep dasar dan syarat-syarat penyelesaiannya, kita dengan mudah menyelesaikan soal tersebut dengan baik. Apabila Quipperian ingin melihat SOLUSI SUPER dari segala pelajaran yang kalian pelajari, jangan ragu untuk bergabung bersama Quipper karena masih banyak TIPS dan Trik beserta SOLUSI SUPER yang dapat membantu kamu memahami tiap pelajaran dan menyelesaikan soal pelajaranmu dengan baik. Sehingga membuat pelajaranmu menjadi gampang, asyik, dan menyenangkan. Ayo gabung bersama <\/span><a href=\"https:\/\/learn.quipper.com\/\"><b>Quipper Video<\/b><\/a><span style=\"font-weight: 400;\">!.<\/span><\/p>\n<ul>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Kanginan, Marthen. 2013. <\/span><i><span style=\"font-weight: 400;\">Fisika Untuk SMA\/MA Kelas XI<\/span><\/i><span style=\"font-weight: 400;\">. Jakarta: Penerbit Erlangga<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Kanginan, Marthen. 2006. <\/span><i><span style=\"font-weight: 400;\">Seribu Pena Fisika SMA Kelas XI Jilid 2<\/span><\/i><span style=\"font-weight: 400;\">. Jakarta: Penerbit Erlangga<\/span><\/li>\n<li style=\"font-weight: 400;\"><span style=\"font-weight: 400;\">Kanginan, Marthen. 2017. <\/span><i><span style=\"font-weight: 400;\">Master Book Physics (Metode Cepat menjadi Master Fisika<\/span><\/i><span style=\"font-weight: 400;\">).\u00a0 Bandung: Yrama Widya<\/span><\/li>\n<\/ul>\n<p><b>Penulis: William Yohanes<\/b><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Halo Quipperian! Pada kesempatan kali ini Quipper Blog akan membahas suatu topik yang menarik lho, yaitu \u201cSolusi Super Menyelesaikan Soal tentang Kinematika Vektor\u201d. Tahukah&hellip;<\/p>\n","protected":false},"author":99400369,"featured_media":276565,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[679384877,679384888],"tags":[679384977],"ppma_author":[679386827],"class_list":["post-276507","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-fisika","category-mapel","tag-materi-fisika-kelas-11"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.3 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Kinematika Vektor - Fisika Kelas 11 - Konsep, Rumus, dan Contoh Soal - Quipper Blog<\/title>\n<meta name=\"description\" content=\"Quipperian, sudah paham dengan materi kinematika belum? 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