{"id":314389,"date":"2023-03-15T08:16:28","date_gmt":"2023-03-15T01:16:28","guid":{"rendered":"https:\/\/quipperhome.wpcomstaging.com\/?p=314389"},"modified":"2023-03-15T08:16:35","modified_gmt":"2023-03-15T01:16:35","slug":"hukum-hess","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/mapel\/kimia\/hukum-hess\/","title":{"rendered":"Hukum Hess: Prinsip, Manfaat, Bunyi, Rumus, dan Contoh Soal"},"content":{"rendered":"\n<figure class=\"wp-block-image size-full is-resized\"><img fetchpriority=\"high\" decoding=\"async\" src=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2023\/03\/education_1098-16770.webp\" alt=\"\" class=\"wp-image-314393\" width=\"780\" height=\"521\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2023\/03\/education_1098-16770.webp 626w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2023\/03\/education_1098-16770-585x390.webp?crop=1 585w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2023\/03\/education_1098-16770-263x175.webp?crop=1 263w\" sizes=\"(max-width: 780px) 100vw, 780px\" \/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Quipperian, apakah saat ini kamu sedang mempelajari materi Kimia tentang termokimia? Jika ya, tentu kamu tidak asing lagi dengan hukum Hess karena materi tersebut berkaitan erat dengan hukum yang dipelopori oleh Germain Henri Hess ini.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Secara singkat, hukum Hess didefinisikan sebagai hukum yang menyatakan bahwa entalpi hanya bergantung pada keadaan awal dan akhir reaksi, bukan proses reaksi. Hukum ini perlu kamu pahami, terutama jika ingin menguasai perhitungan dalam materi termokimia.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Lantas, bagaimana bunyi dan rumusnya? Bagaimana penerapan hukum Hess? Temukan jawabannya dalam ulasan berikut ini.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Pengertian Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Hukum Hess adalah hukum yang menyatakan bahwa entalpi hanya bergantung pada keadaan awal dan akhir reaksi saja, bukan proses terjadinya reaksi tersebut. Dengan kata lain, perubahan entalpi hanya ditentukan oleh kalor pereaksi dan kalor hasil reaksi saja.<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/GMlq-J4x1rq2gtEo6inLQ7NdPBW9d6WVwbQzyr_lU8TsvrcSrqKAwQAH6k4uEJRq2VeJ0_nKxE4wt4HAdSvgfPU6SeEsEByvvVZaQLU5CkU2LFc8BTlpHH8A_ns0IUE9rzbXwFWRMaNatWZGfFRlv5Y\" alt=\"Pengertian hukum hess\" width=\"367\" height=\"287\" title=\"Hukum Hess\/Foto: vedantu.com\"\/><figcaption class=\"wp-element-caption\">source: vedantu.com<\/figcaption><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Entalpi (perubahan energi) sendiri merupakan jumlah energi dalam volume dan tekanan panas dari suatu zat yang dilambangkan dengan huruf H.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Hukum Hess atau disebut juga hukum kekekalan penjumlahan kalor pada dasarnya merupakan bagian dari hukum termodinamika pertama (asas kekekalan energi) yang berkaitan dengan reaksi kimia.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Prinsip Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Adapun prinsip dasar dari hukum Hess ini adalah perubahan energi (entalpi) hanya bergantung pada keadaan awal dan akhir reaksi saja, bukan pada proses reaksinya. Hal ini dikarenakan perubahan entalpi dalam reaksi kimia adalah sama, terlepas dari apakah reaksi tersebut terjadi dalam satu atau beberapa tahap.\u00a0<\/p>\n\n\n\n<div class=\"baca\">\n<p><span class=\"head_baca\">Baca Juga: <\/span> <a href=\"https:\/\/www.quipper.com\/id\/blog\/mapel\/kimia\/hukum-gay-lussac\/\">Hukum Gay Lussac: Bunyi, Sejarah, Ciri-ciri, Rumus, dan Contoh Soal <\/a><\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Manfaat Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Dengan adanya hukum Hess, memudahkan kita untuk mengetahui perubahan entalpi, meskipun tidak mengetahui bagaimana proses yang dijalankan untuk menghasilkan suatu produk.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Meskipun demikian, kita tetap perlu mempertimbangkan berbagai jalur yang dilalui suatu reaksi. Misalnya, reaktan A bereaksi langsung membentuk produk B yang dapat kita sebut sebagai jalur pertama.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Namun, reaktan A ini juga bisa bereaksi dengan reaktan lain, misalnya reaktan Z dan membentuk produk Y. Kemudian, Y bereaksi membentuk Z dan seterusnya hingga berakhir pada jalur terakhirnya.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Nah, dalam hukum Hess, perubahan entalpi dari dua jalur tersebut akan tetap sama. Maka dari itu, entalpi tidak bergantung pada proses reaksi, tapi bergantung pada keadaan awal dan akhir reaksi saja.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Sejarah Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Awal mula terciptanya hukum Hess ini adalah kesulitan yang dialami oleh para ahli kimia dalam menentukan panas pembentukan senyawa dalam percobaan di laboratorium. Oleh karena itu, para ahli kimia ini berusaha mencari jalan keluarnya.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pada tahun 1840, ahli Kimia dari Swiss, yakni Germain Henri Hess berhasil menemukan jalan keluar dari kesulitan tersebut.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Berdasarkan hasil pengukuran dan sifat-sifat entalpi, Hess pun menyatakan bahwa entalpi hanya bergantung pada keadaan awal dan akhir reaksi saja, bukan pada bagaimana proses reaksi tersebut terjadi.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Bunyi Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Adapun bunyi dari hukum Hess adalah sebagai berikut.&nbsp;<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Rumus Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Hukum Hess menyatakan bahwa perubahan entalpi tidak dipengaruhi oleh proses reaksi, tapi dipengaruhi oleh keadaan awal dan akhir reaksi. Maka, rumus hukum Hess dapat dituliskan sebagai berikut:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H = \u0394H<sub>1<\/sub> + \u0394H<sub>2<\/sub> + \u0394H<sub>3<\/sub> + \u2026&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Keterangan:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H = perubahan energi<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H<sub>1<\/sub><sub> <\/sub>= perubahan energi pertama<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H<sub>2<\/sub><sub> <\/sub>= perubahan energi kedua<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H<sub>3<\/sub><sub> <\/sub>= perubahan energi ketiga<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Diagram Hukum Hess<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Untuk mencari \u0394H pada suatu reaksi, kamu bisa menggunakan diagram bertingkat hukum Hess. Misalnya, kamu ingin mencari&nbsp; \u0394H pada pembentukan 2 mol N<sub>2<\/sub>O, maka diagramnya akan terlihat seperti berikut ini.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh4.googleusercontent.com\/zj3W3tUt19fFrlHMPHZq02zNb0WE3e4QEp6Nu8CCKjMCNpyGuc9kCmn3GvN0HuP06mcqvHocgxZhYWkVD5LBSSYyf_wShVSIeH5_ThAxBHIXcCaYpOTg_EUcaNGHR28uA4OF3EDl_tabHFX5cQxuarg\" alt=\"Contoh gambar diagram hukum hess\" title=\"diagram hukum Hess\/Foto: Buku rangkuman kimia SMA\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">Perlu diingat, pada diagram bertingkat, tanda panah ke bawah diberi tanda negatif,\u00a0 sedangkan tanda panah ke atas diberi tanda positif.\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Dari diagram di atas, maka besaran&nbsp; \u0394H untuk pembentukan 2 mol N<sub>2<\/sub>O adalah:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u00bd N<sub>2(g)<\/sub> + O<sub>2(g)<\/sub> \u2192 NO<sub>2(g)<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">-\u0394H<sub>3 <\/sub><sub><\/sub>= -57,05 kJ &#8211; (-90,25 kJ)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">= +33,2 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">N<sub>2(g)<\/sub> + 2O<sub>2(g)<\/sub> \u2192 2NO<sub>2(g)<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Pada pembentukan NO<sub>2<\/sub> menggunakan 2 mol, maka \u0394H harus dikalikan 2 sehingga menjadi:<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H = (-\u0394H<sub>3<\/sub>) x 2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">= (+33,2 kJ) x 2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">= +66,4 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Jadi besaran&nbsp; \u0394H untuk pembentukan 2 mol N<sub>2<\/sub>O adalah +66,4 kJ.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Selain menggunakan diagram bertingkat, reaksi pembentukan 2 mol N<sub>2<\/sub>O juga dapat digambarkan menggunakan siklus. Berikut gambarnya.&nbsp;<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh3.googleusercontent.com\/ATE1VqwIIcrE7Ch0tJSgF0dYwfI5CpaKnK1q6KiUuopOQ3zTi8Qg79gSMzjQBsQ-8xSVHBxfNjURJgR8SxRq61v-dGzmO-DbtZRFL0AFgudrdGfUHNZk-LKYG-M2hiERWhamVSnFR1oued0sK3Nr1D0\" alt=\"Siklus pembentukan reaksi hukum hess\" title=\"siklus hukum hess\/Foto: Buku rangkuman kimia SMA\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Penetapan Hukum Hess<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Berikut adalah beberapa penerapan hukum Hess.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>1. Perubahan entalpi pada perubahan fisika<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Karbon dan intan adalah alotrop dari unsur karbon. Namun, proses pengubahan grafit menjadi intan tidak dapat dilakukan, maka perubahan energi yang terjadi selama konversi tidak dapat diukur.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Meskipun demikian, dengan menggunakan hukum Hess, perubahan panas dari grafit menjadi intan ini dapat dihitung.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>2. Perubahan entalpi pada reaksi kimia<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Hukum Hess juga dapat diterapkan pada perubahan entalpi reaksi kimia. Contohnya, pada reaksi pembentukan hidrogen iodida dari hidrogen dan iodium.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Untuk mengetahui reaksi tersebut bersifat eksoterm atau endoterm, maka dapat dilakukan perhitungan terhadap perubahan panas yang terjadi ketika satu atom hidrogen bereaksi dengan satu atom iodium dalam kondisi normal untuk menghasilkan satu mol hidrogen iodida dalam bentuk gas.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Dari perhitungan yang menerapkan hukum Hess tersebut, dapat diketahui bahwa reaksi pembentukan hidrogen iodida dari hidrogen dan iodium adalah reaksi eksoterm.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>3. Entalpi pembentukan<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Ketika karbon dan hidrogen bercampur, ada berbagai macam hidrokarbon yang dapat terbentuk sehingga panas pembentukan benzena tidak dapat ditentukan secara eksperimental. Oleh karena itu, hukum Hess dapat digunakan untuk menghitung perubahan jumlah panas.\u00a0<\/p>\n\n\n\n<div class=\"baca\">\n<p><span class=\"head_baca\">Baca Juga: <\/span> <a href=\"https:\/\/www.quipper.com\/id\/blog\/mapel\/kimia\/bentuk-molekul-berdasarkan-teori-domain-elektron\/\">Pahami Bentuk Molekul Berdasarkan Teori Domain Elektron<\/a><\/p>\n<\/div>\n\n\n\n<h2 class=\"wp-block-heading\"><strong>Contoh Soal Hukum Hess dan Pembahasannya<\/strong><\/h2>\n\n\n\n<p class=\"wp-block-paragraph\">Untuk mengasah kemampuanmu, yuk simak beberapa contoh soal hukum Hess dan pembahasannya berikut ini.&nbsp;<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Contoh 1<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Diketahui \u0394H<sub>f<\/sub> CO<sub>2<\/sub> = -396 kJ mol<sup>-1<\/sup> dan \u0394H<sub>c<\/sub>&nbsp; CO = -284 kJ mol<sup>-1<\/sup>. Tentukan \u0394H<sub>f<\/sub> CO dengan diagram bertingkat hukum Hess.<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Pembahasan<\/strong><\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/AVjDQzbkcjvA24ZI0jPJHDlWPNKzmGjVLvofgOg39A3nQfNE_8rK7HyW3WFD7N2PWN5hOvQRdkY9C88VAHFVOlkzVYPlQF51DYH4TjOWVPsvdLLwTb1i-yyj_pnpztLnJytGOJzPE6GrOK2-RXanNx8\" alt=\"Contoh soal hukum Hess\" title=\"contoh soal\/Foto: Buku Kimia Itu Asyik SMA Kelas 2\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">\u00a0\u0394H = \u0394H<sub>1<\/sub> &#8211; \u0394H<sub>3<\/sub><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">= (-396kJ) &#8211; (-284 kJ)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">= -112 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Jadi \u0394H<sub>f<\/sub> CO adalah&nbsp; -112 kJ mol<sup>-1<\/sup>.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Contoh 2<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Perhatikan diagram siklus entalpi berikut ini, kemudian tentukan \u0394H<sub>3<\/sub>!<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh5.googleusercontent.com\/CV1AL4O1X_3J0nnw3SRxrtfVLFTld9NTOsf1ChSZWctEAoeCGNGKSpCsxLm0q9G45SQcxYYr2EzfzCudkWDMTomUZBL-lY9KM0wlHS8ECpRaMqUQhY3x4DrI5wBSb8eWJMHTSE8Cnji9bIqZAEkBc8Q\" alt=\"Contoh soal hukum Hess\" title=\"contoh soal\/Foto: Buku Cerdas Belajar Kimia\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Pembahasan<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Reaksi (1) berlangsung dalam satu tahap, yaitu reaksi pembentukan 2 NO<sub>2<\/sub> dari N<sub>2<\/sub> dan 2O<sub>2<\/sub>. Sementara itu, reaksi (2) berlangsung berlangsung melalui tahap pembentukan 2NO terlebih dahulu, kemudian berlanjut ke tahap pembentukan 2NO<sub>2<\/sub>.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H reaksi (1) = \u0394H reaksi (2)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">\u0394H1 = &nbsp; \u0394H3 + \u0394H2<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">66,4 kJ = x + (-114,1 kJ)<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">x = 180,5 kJ<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Jadi, \u0394H<sub>3<\/sub> adalah 180,5 kJ.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><strong>Contoh 3<\/strong><\/h3>\n\n\n\n<p class=\"wp-block-paragraph\">Perhatikan diagram entalpi berikut ini!<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/lh6.googleusercontent.com\/Bzvgc31I1b1RbBGuoOoTuL9Q4xyg2TjhMplD_-ySaMG5x_SGnrno3NkPpmRqKFGwZpjG0YAYgJBRfgMNtB-y4IRjiGD-ST6sT3NfYuJ0g4KSHIcLzx7XgcNMkPEJP3KfCW6h0W9_Uurus5wp9KTRaYE\" alt=\"Contoh soal hukum Hess\" title=\"contoh soal\/Foto: Repositori Kemendikbud\"\/><\/figure>\n\n\n\n<p class=\"wp-block-paragraph\">\u00a0<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Berdasarkan diagram di atas, maka hubungan \u0394H<sub>1 <\/sub>, \u0394H<sub>2 <\/sub>, \u0394H<sub>3<\/sub> adalah\u2026&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\"><strong>Pembahasan<\/strong><\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Dari diagram entalpi dapat diketahui:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Keadaan awal: C<sub>(g)<\/sub> + 2H<sub>2(g)<\/sub> + O<sub>2(g)<\/sub><\/li>\n\n\n\n<li>Keadaan akhir: CO<sub>2(g)<\/sub> + 2H<sub>2<\/sub>O<sub>(<\/sub><sub>l<\/sub><sub>)<\/sub><\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Selain itu ada dua jalur yang terbentuk, yaitu:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Jalur bertahap: \u0394H<sub>1 <\/sub>+ \u0394H<sub>2<\/sub><\/li>\n\n\n\n<li>Jalur langsung: \u0394H<sub>3<\/sub>&nbsp;<\/li>\n<\/ul>\n\n\n\n<p class=\"wp-block-paragraph\">Berdasarkan hukum Hess, maka besarnya entalpi adalah sama. Artinya hubungan \u0394H<sub>1 <\/sub>, \u0394H<sub>2 <\/sub>, \u0394H<sub>3<\/sub> adalah sama atau \u0394H<sub>1 <\/sub>+ \u0394H<sub>2<\/sub> =&nbsp; \u0394H<sub>3<\/sub>.&nbsp;<\/p>\n\n\n\n<p class=\"wp-block-paragraph\">Quipperian, demikian pembahasan mengenai hukum Hess. Semoga pembahasan ini dapat membantu kamu dalam memahami hukum Hess ini, ya.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Quipperian, apakah saat ini kamu sedang mempelajari materi Kimia tentang termokimia? Jika ya, tentu kamu tidak asing lagi dengan hukum Hess karena materi tersebut&hellip;<\/p>\n","protected":false},"author":156447303,"featured_media":314393,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[679384879],"tags":[],"ppma_author":[679386823,679386839],"class_list":["post-314389","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-kimia"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.3 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Hukum Hess: Prinsip, Manfaat, Bunyi, Rumus, dan Contoh Soal - Quipper Blog<\/title>\n<meta name=\"description\" content=\"Hukum Hess adalah hukum yang menyatakan perubahan entalpi hanya ditentukan oleh kalor pereaksi dan kalor hasil reaksi saja. 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