{"id":315560,"date":"2023-05-11T08:30:00","date_gmt":"2023-05-11T01:30:00","guid":{"rendered":"https:\/\/quipperhome.wpcomstaging.com\/?p=315560"},"modified":"2023-05-11T11:58:52","modified_gmt":"2023-05-11T04:58:52","slug":"medan-listrik","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/mapel\/fisika\/medan-listrik\/","title":{"rendered":"Rumus Kuat Medan Listrik Pada Konduktor Berongga dan Keping Sejajar"},"content":{"rendered":"\n
\"Pahami<\/figure>\n\n\n\n

Hai Quipperian, tahukah kamu jika penggaris yang digosokkan ke rambut bisa menarik potongan kertas, lho. Kertas akan tertarik jika penggaris kamu dekatkan, ya. Jika posisi antara penggaris dan kertas terlalu jauh, maka kertas tidak akan tertarik.<\/p>\n\n\n\n

Mengapa demikian? Hal itu karena adanya medan listrik di daerah penggaris. Semakin jauh jarak penggaris dan kertas, medan listriknya akan semakin kecil. Memangnya, apa yang dimaksud medan listrik itu? Daripada penasaran, yuk simak selengkapnya!<\/p>\n\n\n\n

Pengertian Medan Listrik<\/h2>\n\n\n\n

Medan listrik adalah daerah di sekitar muatan listrik yang masih mendapatkan pengaruh gaya listrik. <\/strong>Muatan yang menghasilkan medan listrik disebut sebagai muatan sumber.<\/p>\n\n\n\n

Sementara muatan lain yang berada di daerah muatan sumber dan masih mendapatkan pengaruh gaya listrik disebut muatan uji. Setiap jenis muatan memiliki arah garis medan listrik yang berbeda.<\/p>\n\n\n\n

Untuk muatan negatif, arah medan listriknya masuk. Sementara muatan positif, arah garis medan listriknya keluar. Perhatikan ilustrasi berikut.<\/p>\n\n\n\n

\"arah<\/figure>\n\n\n\n

Ilustrasi yang berwarna hijau menunjukkan arah medan listrik muatan negatif, di mana arah garis medan listriknya masuk ke dalam muatan. Sementara ilustrasi berwarna orange menunjukkan arah medan listrik muatan positif, di mana arah garis medan listriknya keluar muatan.<\/p>\n\n\n\n

Itulah mengapa, jika muatan sejenis kamu dekatkan, akan terjadi gaya tolak menolak karena arah garis medan listrik kedua muatan sama.<\/p>\n\n\n\n

\n

Baca Juga: <\/span> Materi Muatan Listrik, Jenis, Rumus dan Contoh Soal<\/a><\/p>\n<\/div>\n\n\n\n

Medan Listrik antara Muatan Sumber dan Muatan Uji<\/h2>\n\n\n\n

Saat muatan uji didekatkan pada muatan sumber, akan terjadi dua kemungkinan interaksi, yaitu interaksi tolak menolak atau tarik menarik. Perhatikan ilustrasi di bawah ini.<\/p>\n\n\n\n

\"Medan<\/figure>\n\n\n\n

Ilustrasi di atas menggambarkan interaksi tarik menarik antara muatan sumber dan muatan uji karena jenis muatannya tidak sejenis. Lalu, bagaimana ilustrasi untuk muatan sejenis?<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Sampai sini, Quipperian sudah paham kan mekanisme tarik menarik atau tolak menolak antar muatan?<\/p>\n\n\n\n

Rumus Medan Listrik<\/h2>\n\n\n\n

Kuat lemahnya medan listrik bisa dinyatakan sebagai suatu besaran yang disebut kuat medan listrik<\/strong>. Besaran ini termasuk besaran vektor, sehingga arah harus diperhatikan. Kuat medan listrik dipengaruhi oleh nilai muatan sumber dan jaraknya terhadap muatan uji. Secara matematis, dirumuskan sebagai berikut.<\/p>\n\n\n\n

\"Rumus<\/figure>\n\n\n\n

Keterangan Rumus<\/strong><\/p>\n\n\n\n

E = kuat medan listrik (N\/C)<\/p>\n\n\n\n

k = tetapan Coulomb yang nilainya 9 \u00d7 109<\/sup> Nm2<\/sup>\/C2<\/sup><\/p>\n\n\n\n

Q =nilai muatan sumber (C)<\/p>\n\n\n\n

r = jarak antara muatan sumber dan muatan uji (m)<\/p>\n\n\n\n

Kuat Medan Listrik pada Konduktor Berongga<\/h2>\n\n\n\n

Konduktor berongga adalah suatu konduktor yang bagian dalamnya berisi udara atau tidak mengandung muatan. Perhatikan gambar konduktor berongga berikut ini.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Gambar di atas menunjukkan bahwa muatan hanya terdistribusi di bagian permukaan konduktor saja. Mengacu pada ketentuan tersebut, nilai kuat medan listrik pada bola konduktor berongga dibagi menjadi tiga kondisi seperti berikut.<\/p>\n\n\n\n

Kuat Medan Listrik di dalam Konduktor<\/h3>\n\n\n\n

Kuat medan listrik di dalam konduktor (R < r) akan bernilai nol karena di dalam rongganya tidak terdapat muatan. Itu artinya, tidak terdapat muatan sumber.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Rumus : E (R < r) = 0<\/strong><\/p>\n\n\n\n

Kuat Medan Listrik di Permukaan Konduktor<\/h3>\n\n\n\n

Kuat medan listrik di permukaan konduktor berlaku jika R =r seperti berikut.<\/p>\n\n\n\n

\"Kuat<\/figure>\n\n\n\n

Rumus<\/strong><\/p>\n\n\n\n

\"Rumus<\/figure>\n\n\n\n

Kuat Medan Listrik di Luar Bola Berongga<\/h3>\n\n\n\n

Kuat medan listrik di luar bola berongga berlaku jika R >r.<\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Rumus<\/strong><\/p>\n\n\n\n

\"Rumus<\/figure>\n\n\n\n

Dengan<\/p>\n\n\n\n

R = jarak antara permukaan konduktor titik di luar konduktor yang dimaksud.<\/p>\n\n\n\n

Kuat Medan Listrik pada Keping Sejajar<\/h2>\n\n\n\n

Keping sejajar adalah dua keping yang memiliki perbedaan muatan. Keping sejajar ini telah dikembangkan menjadi komponen elektronik bernama kapasitor yang berfungsi untuk menyimpan muatan. Secara matematis, kuat medan listrik antara keping sejajar dirumuskan sebagai berikut.<\/p>\n\n\n\n

Rumus Kuat Medan Listrik pada Keping Sejajar<\/strong><\/p>\n\n\n\n

\"\"<\/figure>\n\n\n\n

Keterangan Rumus<\/strong><\/p>\n\n\n\n

\u03c3 = rapat muatan (C\/m2)<\/p>\n\n\n\n

\u03b50<\/sub> = permitivitas ruang hampa yang nilainya (8,85 \u00d7 10-12<\/sup> C2<\/sup>\/Nm2<\/sup>)<\/p>\n\n\n\n

Oleh karena rapat muatan listrik \u03c3 = Q \/ A, maka persamaannya bisa diubah menjadi<\/p>\n\n\n\n

\"Persamaan<\/figure>\n\n\n\n

Keterangan Rumus<\/strong><\/p>\n\n\n\n

Q = muatan listrik (C)<\/p>\n\n\n\n

A = luas keping sejajar (m2<\/sup>)<\/p>\n\n\n\n

\n

Baca Juga: <\/span> Pengertian Resistansi, Rumus, Lambang dan Satuannya<\/a><\/p>\n<\/div>\n\n\n\n

Contoh Soal Medan Listrik<\/h2>\n\n\n\n

Untuk mengasah pemahamanmu, yuk simak contoh soal di bawah ini.<\/p>\n\n\n\n

Contoh Soal Pertama<\/h3>\n\n\n\n

Suatu muatan uji diletakkan sejauh 40 cm dari muatan sumber. Jika nilai muatan sumber dan muatan ujinya berturut-turut adalah 3 \u03bcC dan 5 \u03bcC, tentukan kuat medan listrik yang dirasakan muatan uji.<\/p>\n\n\n\n

Diketahui<\/p>\n\n\n\n

QS<\/sub> = 3 \u03bcC = 3 \u00d7 10-6<\/sup> C<\/p>\n\n\n\n

QU<\/sub> = 5 \u03bcC = 5 \u00d7 10-6<\/sup> C<\/p>\n\n\n\n

r = 40 cm = 0,4 m<\/p>\n\n\n\n

Ditanya E =\u2026?<\/p>\n\n\n\n

Jawaban<\/strong><\/p>\n\n\n\n

Untuk mencari kuat medan listrik, gunakan persamaan berikut<\/p>\n\n\n\n

\"Jawaban<\/figure>\n\n\n\n

Jadi, kuat medan listriknya adalah 0,169 N\/C<\/p>\n\n\n\n

Contoh Soal Kedua<\/h3>\n\n\n\n

Suatu bola konduktor berongga memiliki jari-jari 25 cm. Jika muatan di permukaan konduktor tersebut 15 \u03bcC, tentukan perbandingan kuat medan listrik di permukaan konduktor dan di titik berjarak 5 cm di luar konduktor!<\/p>\n\n\n\n

Diketahui :<\/p>\n\n\n\n

r = 25 cm<\/p>\n\n\n\n

R = 5 + 25 = 30 cm (dari pusat bola)<\/p>\n\n\n\n

Q = 15 \u03bcC = 15 \u00d7 10-6<\/sup> C<\/p>\n\n\n\n

Ditanya: Epemukaan<\/sub> : Edi luar<\/sub> =\u2026?<\/p>\n\n\n\n

Jawaban<\/strong><\/p>\n\n\n\n

Untuk menentukan perbandingannya, gunakan persamaan berikut.<\/p>\n\n\n\n

\"Jawaban<\/figure>\n\n\n\n

Jadi, perbandingannya adalah 36 : 25.<\/p>\n\n\n\n

Contoh Soal Ketiga<\/h3>\n\n\n\n

Suatu keping sejajar memiliki luas penampang 5 x 10-4<\/sup> m2<\/sup>. Jika keping sejajar itu menyimpan muatan sebesar 1,2 \u03bcC, tentukan kuat medan listrik di antara keping tersebut!<\/p>\n\n\n\n

Diketahui :<\/p>\n\n\n\n

A = 5 x 10-4<\/sup> m2<\/sup><\/p>\n\n\n\n

Q = 1,2 \u03bcC = 1,2 \u00d7 10-6 <\/sup>C<\/p>\n\n\n\n

Ditanya: E =\u2026?<\/p>\n\n\n\n

Jawaban<\/strong><\/p>\n\n\n\n

Kuat medan listrik di antara keping sejajar tersebut dinyatakan sebagai berikut.<\/p>\n\n\n\n

\"Jawaban<\/figure>\n\n\n\n

Jadi, kuat medan listrik di antara dua keping tersebut adalah 2,7 \u00d7 108<\/sup> N\/C<\/p>\n\n\n\n

Itulah pembahasan Quipper Blog kali ini. Semoga bermanfaat, ya. Untuk mendapatkan materi lengkapnya, yuk buruan gabung Quipper Video. Salam Quipper!<\/p>\n","protected":false},"excerpt":{"rendered":"

Hai Quipperian, tahukah kamu jika penggaris yang digosokkan ke rambut bisa menarik potongan kertas, lho. Kertas akan tertarik jika penggaris kamu dekatkan, ya. Jika…<\/p>\n","protected":false},"author":156742495,"featured_media":315600,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[679384877],"tags":[],"ppma_author":[679386821,679386838],"class_list":["post-315560","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-fisika"],"acf":[],"yoast_head":"\nRumus Kuat Medan Listrik Pada Konduktor Berongga dan Keping Sejajar<\/title>\n<meta name=\"description\" content=\"Materi fisika tentang Rumus Medan Listrik dan kuat medan listrik pada Konduktor Berongga dan pada Keping Sejajar dan contoh soal pembahasannya\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, 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