{"id":35362,"date":"2016-10-31T18:41:20","date_gmt":"2016-10-31T11:41:20","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=35362"},"modified":"2021-11-24T20:09:33","modified_gmt":"2021-11-24T13:09:33","slug":"yuk-persiapkan-uas-kamu-dengan-belajar-contoh-soal-uas-fisika-kelas-x-semester-1-dari-bab-gerak","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/mapel\/yuk-persiapkan-uas-kamu-dengan-belajar-contoh-soal-uas-fisika-kelas-x-semester-1-dari-bab-gerak\/","title":{"rendered":"Yuk Persiapkan UAS Kamu dengan belajar Contoh Soal UAS Fisika Kelas X Semester 1 dari Bab Gerak"},"content":{"rendered":"<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291.jpg\" data-rel=\"penci-gallery-image-content\" ><img fetchpriority=\"high\" decoding=\"async\" class=\"size-full wp-image-35382 aligncenter\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291.jpg\" alt=\"Yuk Persiapkan UAS Kamu dengan belajar Contoh Soal UAS Fisika Kelas X Semester 1 dari Bab Gerak\" width=\"800\" height=\"533\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291.jpg 800w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291-768x512.jpg 768w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291-585x390.jpg?crop=1 585w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/40b37-imageedit_3_7583565291-263x175.jpg?crop=1 263w\" sizes=\"(max-width: 800px) 100vw, 800px\" \/><\/a><\/p>\n<p><b><\/b><span style=\"font-weight:400;\">Apakah Quipperian kelas X sudah mempersiapkan diri untuk UAS Fisika? Masih bingung soal seperti apa yang kiranya akan muncul? Tenang, kali ini Quipper Video Blog akan memberikan beberapa contoh soal UAS Fisika Kelas X Semester Ganjil yang sering muncul. Pada postingan kali ini, Quipper Video Blog akan menyajikan beberapa soal dari Bab Gerak.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Sebelum masuk ke dalam contoh soal, kamu harus tahu bahwa dalam pelajaran Fisika kamu akan menemukan tiga jenis soal. Pertama ialah jenis soal definisi dan pengertian, dan kedua berkaitan dengan penggunaan rumus. Untuk itu, kamu harus memahami dua hal itu bila ingin mendapatkan nilai bagus di UAS Fisika nanti.<\/span><\/p>\n<h2><b>Contoh Soal Definisi dan Pengertian<\/b><\/h2>\n<h2><b><b>1)<br \/>\n<\/b><\/b><\/h2>\n<p><b><b>Gerakan suatu benda dimana setiap titik pada benda tersebut mempunyai jarak yang tetap terhadap suatu sumbu tertentu, merupakan pengertian dari:<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) Gerak Translasi<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) Gerak Rotasi<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) Perpindahan<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) Kelajuan<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) Kecepatan<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari soal tersebut termasuk soal yang sangat mudah. Kata kuncinya terdapat pada kalimat \u201csuatu sumbu tertentu\u201d. Dari kata kunci itu terlihat bahwa jawaban yang tepat adalah <\/span><b>B<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>2)<br \/>\n<\/b><\/h2>\n<p><b><b>Dari pilihan jawaban berikut, manakah yang merupakan definisi atau pengertian dari Kelajuan Sesaat:<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) kelajuan rata-rata yang waktu tempuhnya mendekati nol<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) kelajuan rata-rata hasil dari perpindahan dari satu tempat ke tempat lainnya<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) hasil bagi jarak total yang ditempuh dengan waktu tempuhnya<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) hasil bagi perpindahan dengan selang waktu<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) jarak yang ditempuh dengan waktu tempuhnya<\/span><\/p>\n<p><span style=\"font-weight:400;\">Untuk soal tersebut, jawaban yang tepat adalah <\/span><b>A<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>3)<\/b><\/h2>\n<p><b><b>Gerak suatu benda pada garis lurus dengan kecepatan tetap merupakan pengertian dari:<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) Gerak Translasi<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) Gerak Melingkar<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) Kecepatan<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) Gerak Lurus Berubah Beraturan (GLBB)<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) Gerak Lurus Beraturan (GLB)<\/span><\/p>\n<p><span style=\"font-weight:400;\">Soal ini juga termasuk mudah. Jawaban yang tepat untuk soal tersebut ialah <\/span><b>E<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari tiga jenis soal itu terlihat bahwa jenis soal definisi sangat mudah, yakni berkutat pada pengertian dan definisi dasar dari berbagai teori dalam materi pembelajaran. Selain jenis soal tersebut, terdapat pula jenis soal definisi atau pengertian yang bentuk pilihan jawabannya berupa gambar grafik.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Berikut contoh soalnya:<\/span><\/p>\n<ul>\n<li><b><b>Perhatikan grafik berikut:<\/b><\/b><\/li>\n<\/ul>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/2200a-grafik-soal-glb-glbb-no-4.jpg\" data-rel=\"penci-gallery-image-content\" ><img decoding=\"async\" class=\"alignnone size-full wp-image-35372\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2016\/10\/2200a-grafik-soal-glb-glbb-no-4.jpg\" alt=\"grafik soal glb glbb no 4\" width=\"321\" height=\"260\"><\/a><\/p>\n<p><b>Sebuah mobil yang sedang bergerak dinyatakan dengan grafik. Mobil melakukan Gerak Lurus Beraturaran kemudian Gerak Lurus Berubah Beraturan. Dari grafik tersebut di atas, manakah jawaban yang tepat:<\/b><\/p>\n<ol>\n<li style=\"font-weight:400;\"><span style=\"font-weight:400;\">1 dan 2<\/span><\/li>\n<li style=\"font-weight:400;\"><span style=\"font-weight:400;\">1 dan 3<\/span><\/li>\n<li style=\"font-weight:400;\"><span style=\"font-weight:400;\">1 dan 4<\/span><\/li>\n<li style=\"font-weight:400;\"><span style=\"font-weight:400;\">2 dan 3<\/span><\/li>\n<li style=\"font-weight:400;\"><span style=\"font-weight:400;\">3 dan 1<\/span><\/li>\n<\/ol>\n<p><span style=\"font-weight:400;\">Untuk jawaban yang tepat untuk soal tersebut ialah pilihan <\/span><b>E<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Soal-soal definisi dan pengertian ini sebenarnya tidak terlalu mendominasi keseluruhan soal UAS Fisika Kelas X Semester Ganjil. Bila dipersentasekan, soal tipe ini kurang lebih ada sekitar 20-40 persen.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Meski demikian, bukan berarti tipe soal seperti itu dilupakan begitu saja. Sebab, tipe soal tersebut menunjukkan seberapa besar pemahaman kamu akan definisi dan pengertian istilah-istilah dalam ilmu Fisika.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jadi, kamu tetap harus mempersiapkan diri akan soal-soal seperti ini. Biasanya, soal definisi dan pengertian ini cukup mudah dijawab kalau kamu sudah memahami tiap materi bab Gerak.<\/span><\/p>\n<h2><b>Contoh Soal Hitung-Menghitung<\/b><\/h2>\n<p><span style=\"font-weight:400;\">Tipe soal hitung-menghitung ini cukup mendominasi dalam tiap ujian fisika, baik UTS maupun UAS. Nah, untuk UAS, persentasenya bisa mencapai 80 persen. Untuk itu, kamu harus benar-benar paham berbagai rumus fisika yang diajarkan di dalam kelas. Berikut beberapa contoh soal tersebut:<\/span><\/p>\n<h2><b>1)<\/b><\/h2>\n<p><b><b>Sebuah partikel berputar &nbsp;dengan 240 rpm. Jika jari-jari lintasannya 2 m, maka kelajuan linier partikel tersebut adalah:<\/b><\/b><\/p>\n<p>A) 2 <span style=\"font-weight:400;\">\u03c0<\/span> m\/s<\/p>\n<p>B) 4 \u03c0 m\/s<\/p>\n<p>C) 6 \u03c0 m\/s<\/p>\n<p>D) 8 <span style=\"font-weight:400;\">\u03c0<\/span> m\/s<\/p>\n<p>E) 16 <span style=\"font-weight:400;\">\u03c0<\/span> m\/s<\/p>\n<p><span style=\"font-weight:400;\">Untuk menyelesaikan soal tersebut kamu harus menggunakan rumus berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Diketahui:<\/span><\/p>\n<p><span style=\"font-weight:400;\">f = 240 rpm = &nbsp;<\/span><\/p>\n<p><span style=\"font-weight:400;\">r = 2 m<\/span><\/p>\n<p><span style=\"font-weight:400;\">Ditanya:<\/span><\/p>\n<p><span style=\"font-weight:400;\">v = &#8230; ?<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawab:<\/span><\/p>\n<p><span style=\"font-weight:400;\">\u03c9<\/span><span style=\"font-weight:400;\"> = 2\u03c0f = 2 . \u03c0 . 4 = 8\u03c0 rad\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">v = <\/span><span style=\"font-weight:400;\"> . r = 8\u03c0 . 2 = 16\u03c0 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari penghitungan tersebut maka jawaban yang benar adalah <\/span><b>E<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>2)<\/b><\/h2>\n<p><b><b>Sebuah mobil mulai bergerak dari keadaan diam dengan percepatan tetap 24 m\/s2. Maka kecepatan mobil setelah bergerak selama 18 sekon adalah:<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) 2 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) 24 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) 36 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) 42 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) 56 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">Penyelesaian soal tersebut ialah sebagai berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Diketahui: v<\/span><span style=\"font-weight:400;\">0<\/span><span style=\"font-weight:400;\"> = 0; a = 24 m\/s ; &nbsp;t = 18 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">Ditanya: v<\/span><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\"> = &#8230; ?<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawab: v<\/span><span style=\"font-weight:400;\">t<\/span> <span style=\"font-weight:400;\">= v0 + at<\/span><\/p>\n<p><span style=\"font-weight:400;\">= 0 + (24 m\/s2) (18 s)<\/span><\/p>\n<p><span style=\"font-weight:400;\"> &nbsp;&nbsp;&nbsp;&nbsp;v<\/span><span style=\"font-weight:400;\">t<\/span> <span style=\"font-weight:400;\">= 42 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dengan begitu, jawaban yang tepat ialah <\/span><b>D<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>3)<\/b><\/h2>\n<p><b><b>Suatu kereta api sedang bergerak dengan kelajuan 17 m\/s. Ketika melewati tanda akan memasuki stasiun, masinis memperlambat kelajuan kereta api sebesar 2,00 m\/s2. Waktu yang diperlukan kereta api sampai kereta api benar-benar berhenti adalah &#8230; s.<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) 3,5<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) 8<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) 8,5<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) 14<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) 14,5<\/span><\/p>\n<p><span style=\"font-weight:400;\">Mencari jawaban untuk soal tersebut, kamu harus menggunakan rumus berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Diketahui<\/span> <span style=\"font-weight:400;\">: v<\/span><span style=\"font-weight:400;\">0<\/span> <span style=\"font-weight:400;\">= 17 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\"> &nbsp;v<\/span><span style=\"font-weight:400;\">t<\/span> <span style=\"font-weight:400;\">= 0 &nbsp;&nbsp;m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\"> &nbsp;a<\/span> <span style=\"font-weight:400;\">= &#8211; 2 m\/s<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> (perlambatan)<\/span><\/p>\n<p><span style=\"font-weight:400;\">Ditanya<\/span> <span style=\"font-weight:400;\">: t ?<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawab<\/span> <span style=\"font-weight:400;\">:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari hasil hitungan rumus tersebut maka jawabannya ialah <\/span><b>C<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>4)<\/b><\/h2>\n<p><b><b>Waktu yang diperlukan sebuah mobil yang bergerak dengan percepatan 2 m\/s<\/b><b>2<\/b><b>, untuk mengubah kecepatannya dari 10 m\/s menjadi 30 m\/s adalah:<\/b><\/b><\/p>\n<p><span style=\"font-weight:400;\">A) 10 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">B) 20 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">C) 30 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">D) 40 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">E) 50 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">Penyelesaian soal tersebut dapat dilakukan dengan rumus berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">Diketahui<\/span> <span style=\"font-weight:400;\">: <\/span><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\">= 30 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\"> &nbsp;<\/span><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">= 10 m\/s<\/span><\/p>\n<p><span style=\"font-weight:400;\"> &nbsp;&nbsp;<\/span><span style=\"font-weight:400;\">a<\/span><span style=\"font-weight:400;\"> = 2 m\/s<\/span><span style=\"font-weight:400;\">2<\/span><\/p>\n<p><span style=\"font-weight:400;\">Ditanya<\/span> <span style=\"font-weight:400;\">: <\/span><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\">=\u2026?<\/span><\/p>\n<p><span style=\"font-weight:400;\">Jawab<\/span> <span style=\"font-weight:400;\">:<\/span><\/p>\n<p><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\">= <\/span><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">+ <\/span><span style=\"font-weight:400;\">at<\/span><\/p>\n<p><b>karena mencari <\/b><span style=\"font-weight:400;\">t<\/span><b> maka rumusnya berubah menjadi<\/b><\/p>\n<p><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\"> = <\/span><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">t<\/span><span style=\"font-weight:400;\">&#8211;<\/span><span style=\"font-weight:400;\">V<\/span><span style=\"font-weight:400;\">o<\/span><span style=\"font-weight:400;\">a<\/span><span style=\"font-weight:400;\"> = <\/span><span style=\"font-weight:400;\">30-10<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\"> = <\/span><span style=\"font-weight:400;\">10 s<\/span><\/p>\n<p><span style=\"font-weight:400;\">jadi, jawaban yang tepat untuk soal tersebut adalah <\/span><b>A<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Itulah empat contoh soal yang biasanya keluar dalam UAS Fisika Kelas X Semester 1 Bab Gerak. Tentunya, ada beberapa varian rumus lainnya yang harus kamu ketahui juga untuk berjaga-jaga dan mempersiapkan diri. <\/span><\/p>\n<p><span style=\"font-weight:400;\">Bila ingin mendalami materi fisika untuk persiapan UAS, kamu bisa mengikuti video pembelajaran di <a href=\"https:\/\/video.quipper.com\/id\" target=\"_blank\" rel=\"noopener noreferrer\">Quipper Video<\/a> dan mengerjakan latihan soalnya.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Melakukan itu secara rutin, pastinya kamu akan lebih siap menghadapi UAS Fisika nanti. Jadi, tetap semangat ya Quipperian!<\/span><\/p>\n<p><b>Penulis: Muhammad Khairil<\/b><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Apakah Quipperian kelas X sudah mempersiapkan diri untuk UAS Fisika? Masih bingung soal seperti apa yang kiranya akan muncul? Tenang, kali ini Quipper Video&hellip;<\/p>\n","protected":false},"author":156446345,"featured_media":35382,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[679384888,679384882],"tags":[],"ppma_author":[679386822],"class_list":["post-35362","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mapel","category-soal-uas"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.6 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Contoh Soal UAS Fisika Kelas X Semester 1 dari Bab Gerak<\/title>\n<meta name=\"description\" content=\"Pelajaran Fisika tidak bisa dianggap enteng. 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