{"id":70652,"date":"2017-03-22T14:49:13","date_gmt":"2017-03-22T07:49:13","guid":{"rendered":"https:\/\/video.quipper.com\/id\/blog\/?p=70652"},"modified":"2021-11-24T21:51:07","modified_gmt":"2021-11-24T14:51:07","slug":"mau-siap-menghadapi-un-matematika-ini-5-contoh-soal-vektor-matematika-sma-kelas-10","status":"publish","type":"post","link":"https:\/\/quipperhome.wpcomstaging.com\/matematika-un-sma\/mau-siap-menghadapi-un-matematika-ini-5-contoh-soal-vektor-matematika-sma-kelas-10\/","title":{"rendered":"Mau Siap Menghadapi UN Matematika? Ini 5 Contoh Soal Vektor Matematika SMA Kelas 10!"},"content":{"rendered":"<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/a9251-un-matematika-2017.png\" data-rel=\"penci-gallery-image-content\" ><img fetchpriority=\"high\" decoding=\"async\" class=\"size-full wp-image-71482 aligncenter\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/a9251-un-matematika-2017.png\" alt=\"Mau Siap Menghadapi UN Matematika 2017 Bab Vektor? Yuk, Simak Lima Contoh Soal Ini!\" width=\"796\" height=\"518\" srcset=\"https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/a9251-un-matematika-2017.png 796w, https:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/a9251-un-matematika-2017-768x500.png 768w\" sizes=\"(max-width: 796px) 100vw, 796px\" \/><\/a><\/p>\n<p>Quipperian, bagaimana persiapanmu untuk menghadapi Ujian Nasional (UN) 2017 pelajaran matematika? Masih bingung? Merasa belum siap? Tenang saja, ada Quipper Video Blog yang akan membantumu.<\/p>\n<p><span style=\"font-weight:400;\">Pada artikel kali ini, Quipper akan membahas tentang contoh soal bab vektor dalam pelajaran matematika. Dengan mempelajari beberapa contoh soal ini, semoga saja dapat membuatmu lebih percaya diri menghadapi UN Matematika 2017. Langsung saja, yuk, disimak!<\/span><\/p>\n<h2><b>Soal 1<\/b><\/h2>\n<p><b> Jika a = i &#8211; 2j + k, b = 2i &#8211; 2j &#8211; 3k dan c = -i + j + 2k, maka 2a &#8211; 3b &#8211; 5 c sama dengan:<\/b><\/p>\n<p><span style=\"font-weight:400;\">A. i + j + k<\/span><\/p>\n<p><span style=\"font-weight:400;\">B. 2i &#8211; 5j + k<\/span><\/p>\n<p><span style=\"font-weight:400;\">C. 5i &#8211; 2j + k<\/span><\/p>\n<p><span style=\"font-weight:400;\">D. 5i + 2j + k<\/span><\/p>\n<p><span style=\"font-weight:400;\">E. i &#8211; 2 j \u2013 k<\/span><\/p>\n<p><span style=\"font-weight:400;\">Untuk menjawab soal itu, Quipperian harus memperhatikan pembahasannya berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">2a &#8211; 3b &#8211; 5 c = 2 (i &#8211; 2j + k) -3(2i &#8211; 2j &#8211; 3k) &#8211; 5(-i + j + 2k)<\/span><\/p>\n<p><span style=\"font-weight:400;\">2a &#8211; 3b &#8211; 5c = 2i &#8211; 4j + 2k &#8211; 6i + 6j + 9k + 5i &#8211; 5j &#8211; 10k = i + j + k<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari hasil hitungan itu, maka jawaban yang tepat ialah <\/span><b>A<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>Soal 2<\/b><\/h2>\n<p><b> Misalkan D adalah titik berat segitiga ABC dimana A(2,3,-2), B(-4,1,2) dan C(8,5,-3). Panjang vektor posisi d sama dengan:<\/b><\/p>\n<p><span style=\"font-weight:400;\">A. 3<\/span><\/p>\n<p><span style=\"font-weight:400;\">B. 5<\/span><\/p>\n<p><span style=\"font-weight:400;\">C. \u221a5<\/span><\/p>\n<p><span style=\"font-weight:400;\">D. \u221a14<\/span><\/p>\n<p><span style=\"font-weight:400;\">E. \u221a13<\/span><\/p>\n<p><span style=\"font-weight:400;\">Agar dapat menjawab soal ini, hal pertama yang harus kamu lakukan ialah mencari titik D terlebih dahulu. Titik D merupakan titik berat segitiga dalam soal tersebut. Maka, D= 1\/3 (A + B + C).<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari temuan rumus itu, kamu tinggal memasukkan nilai dari masing-masing titik A, B, dan C. Berikut cara menghitungnya:<\/span><\/p>\n<p><span style=\"font-weight:400;\">D = 1\/3 (2,3,-2) + (-4,1,2) + (8,5,-3)<\/span><\/p>\n<p><span style=\"font-weight:400;\">D = 1\/3 (6,9,-3) = (2,3,-1)<\/span><\/p>\n<p><span style=\"font-weight:400;\">Setelah menemukan titik D, hitungan yang harus kamu lakukan selanjutnya ialah panjang proyeksi titik D. <\/span><\/p>\n<p><span style=\"font-weight:400;\">Berikut cara penghitungannya:<\/span><\/p>\n<p><a href=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/4287b-angka.png\" data-rel=\"penci-gallery-image-content\" ><img decoding=\"async\" class=\"alignnone wp-image-71462\" src=\"http:\/\/quipperhome.wpcomstaging.com\/wp-content\/uploads\/2017\/03\/4287b-angka.png\" alt=\"Mau Siap Menghadapi UN Matematika 2017 Bab Vektor? Yuk, Simak Lima Contoh Soal Ini!\" width=\"191\" height=\"52\"><\/a><\/p>\n<p><span style=\"font-weight:400;\">Dari pilihan jawaban yang ada maka jawaban yang tepat untuk soal tersebut ialah <\/span><b>D<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h3 class=\"entry-title\"><a href=\"https:\/\/video.quipper.com\/id\/blog\/un\/jangan-anggap-remeh-materi-ini-di-ujian-nasional-matematika-besok\/\" target=\"_blank\" rel=\"noopener\">Jangan Anggap Remeh Materi Ini di Ujian Nasional Matematika Besok!<\/a><\/h3>\n<h2><b>Soal 3<\/b><\/h2>\n<p><b>Diketahui dua vektor u = 4i &#8211; mj + 2 k dan v = 5i + 2j &#8211; 4k saling tegak lurus. Maka harga m adalah:<\/b><\/p>\n<p><span style=\"font-weight:400;\">A. 10<\/span><\/p>\n<p><span style=\"font-weight:400;\">B. 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">C. 5<\/span><\/p>\n<p><span style=\"font-weight:400;\">D. 9<\/span><\/p>\n<p><span style=\"font-weight:400;\">E. 1<\/span><\/p>\n<p><span style=\"font-weight:400;\">Merujuk pada soal tersebut, vektor u dan v saling tegak lurus maka rumusnya sama seperti: u.v = 0. Dengan begitu, untuk mencari harga m, maka rumus tersebutlah yang digunakan dengan memasukkan persamaan yang telah diketahui. Hitungannya menjadi seperti berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">u . v = 0<\/span><\/p>\n<p><span style=\"font-weight:400;\">(4i &#8211; mj + 2k) (5i + 2j &#8211; 4k) = 20 &#8211; 2m &#8211; 8 = 0 <\/span><\/p>\n<p><span style=\"font-weight:400;\">m = 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari hasil hitungan tersebut maka pilihan jawaban yang tC. epat ialah <\/span><b>B<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h2><b>Soal 4<\/b><\/h2>\n<p><b>Diketahui A (1,2,3), B(3,3,1) dan C(7,5,-3). Jika A, B, dan C segaris, perbandingan AB : BC =&#8230;<\/b><\/p>\n<p><span style=\"font-weight:400;\">A. 5 : 2<\/span><\/p>\n<p><span style=\"font-weight:400;\">B. 2 : 1<\/span><\/p>\n<p><span style=\"font-weight:400;\">C. 1 : 2<\/span><\/p>\n<p><span style=\"font-weight:400;\">D. 5 : 7<\/span><\/p>\n<p><span style=\"font-weight:400;\">E. 7 : 3<\/span><\/p>\n<p><span style=\"font-weight:400;\">Untuk menyelesaikan soal tersebut, maka hitungan rumusnya sebagai berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">AB = B &#8211; A = (3,3,1) &#8211; (1,2,3) = (2,1,-2)<\/span><\/p>\n<p><span style=\"font-weight:400;\">Besar AB = \u221a22 + 12 + (-2)2 = 3 <\/span><\/p>\n<p><span style=\"font-weight:400;\">BC = C &#8211; B = (7,5,-3) &#8211; (3,3,1) = (4,2,-4)<\/span><\/p>\n<p><span style=\"font-weight:400;\">Besar BC = \u221a42 + 22 + (-4)2 = 6<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari hasil hitungan tersebut maka perbandingan AB : BC = 3 : 6 = 1 : 2. Dengan demikian, jawaban yang tepat untuk soal tersebut ialah pilihan <\/span><b>C<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<h3 class=\"entry-title\"><a href=\"https:\/\/video.quipper.com\/id\/blog\/un\/matematika-un-sma\/yuk-belajar-mencintai-matematika-agar-kamu-siap-menghadapi-un-2017\/\" target=\"_blank\" rel=\"noopener\">Yuk Belajar Mencintai Matematika Agar Kamu Siap Menghadapi UN 2017!<\/a><\/h3>\n<h2><b>Soal 5<\/b><\/h2>\n<p><b> Ditentukan A(4 , 7 , 0) , B(6 , 10 , \u20136) dan C(1 , 9 , 0). AB dan AC wakil-wakil dari vektor u dan v. Besar sudut antara u dan v adalah:<\/b><\/p>\n<p><span style=\"font-weight:400;\">A. \u03a0<\/span><\/p>\n<p><span style=\"font-weight:400;\">B. 0<\/span><\/p>\n<p><span style=\"font-weight:400;\">C. 1\/4 \u03c0<\/span><\/p>\n<p><span style=\"font-weight:400;\">D. 1\/2 \u03c0<\/span><\/p>\n<p><span style=\"font-weight:400;\">E. 3\/4 \u03c0<\/span><\/p>\n<p><span style=\"font-weight:400;\">Agar dapat menjawab soal tersebut, hal pertama yang harus Quipperian lakukan ialah tentukan vektor u dan v terlebih dahulu dengan rumus berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">u = AB = B \u2212 A = (6 , 10 , \u20136) \u2212 (4 , 7 , 0) = (2, 3, \u22126) \u2192 u = 2i + 3j \u2212 6k<\/span><\/p>\n<p><span style=\"font-weight:400;\">v = AC = C \u2212 A = (1 , 9 , 0) \u2212 (4 , 7 , 0) = (\u2212 3, 2, 0) \u2192 v = \u2212 3i + 2j<\/span><\/p>\n<p><span style=\"font-weight:400;\">Setelah itu, barulah mencari besar sudut u dan v dengan menggunakan rumus berikut:<\/span><\/p>\n<p><span style=\"font-weight:400;\">cos<\/span> <span style=\"font-weight:400;\">\u03b1= <\/span><span style=\"font-weight:400;\">u.v<\/span><span style=\"font-weight:400;\">|<\/span><span style=\"font-weight:400;\">u<\/span><span style=\"font-weight:400;\">||<\/span><span style=\"font-weight:400;\">v<\/span><span style=\"font-weight:400;\">|<\/span><\/p>\n<p><span style=\"font-weight:400;\">cos<\/span> <span style=\"font-weight:400;\">\u03b1= <\/span><span style=\"font-weight:400;\">(<\/span><span style=\"font-weight:400;\">2i + 3j &#8211; 6k<\/span><span style=\"font-weight:400;\">)<\/span><span style=\"font-weight:400;\">(- 3i + 2j) <\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">+ <\/span><span style=\"font-weight:400;\">3<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">+<\/span><span style=\"font-weight:400;\">(<\/span><span style=\"font-weight:400;\">&#8211; <\/span><span style=\"font-weight:400;\">6<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">)<\/span><span style=\"font-weight:400;\">(<\/span><span style=\"font-weight:400;\">-3<\/span><span style=\"font-weight:400;\">)<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">+<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">2<\/span><span style=\"font-weight:400;\">+<\/span><span style=\"font-weight:400;\">0<\/span><span style=\"font-weight:400;\">2<\/span><\/p>\n<p><span style=\"font-weight:400;\">cos<\/span> <span style=\"font-weight:400;\">\u03b1= <\/span><span style=\"font-weight:400;\">-6+6+0<\/span><span style=\"font-weight:400;\">49<\/span> <span style=\"font-weight:400;\">12<\/span> <span style=\"font-weight:400;\">= <\/span><span style=\"font-weight:400;\">0<\/span><span style=\"font-weight:400;\">7<\/span><span style=\"font-weight:400;\">12<\/span><span style=\"font-weight:400;\">=0<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dari hasil hitungan tersebut, sudut dengan nilai cosinus nol adalah <\/span><span style=\"font-weight:400;\">90<\/span><span style=\"font-weight:400;\">0<\/span><span style=\"font-weight:400;\"> atau sama dengan<\/span> <span style=\"font-weight:400;\">1\/2 \u03c0. Jadi, jawaban yang tepat untuk soal tersebut ialah <\/span><b>D<\/b><span style=\"font-weight:400;\">.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Itulah lima contoh soal UN Matematika 2017 mengenai bab vektor. Bila kamu ingin melatih diri dan mempersiapkan diri dengan matang untuk menghadapi UN, maka kamu bisa berlatih bersama Quipper Video. Sebab, di dalamnya terdapat banyak contoh soal dan materi mengenai mata pelajaran matematika, khususnya bab vektor.<\/span><\/p>\n<p><span style=\"font-weight:400;\">Dengan persiapan yang matang, pastinya nilai sempurna bisa kamu raih. Tetap semangat ya Quipperian belajarnya!<\/span><\/p>\n<p><b>Penulis: Muhammad Khairil<\/b><br \/>\n<b><\/b><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Quipperian, bagaimana persiapanmu untuk menghadapi Ujian Nasional (UN) 2017 pelajaran matematika? Masih bingung? Merasa belum siap? Tenang saja, ada Quipper Video Blog yang akan&hellip;<\/p>\n","protected":false},"author":156446345,"featured_media":71482,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"_crdt_document":"","_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"_jetpack_feature_clip_id":0,"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[677999210],"tags":[],"ppma_author":[679386822],"class_list":["post-70652","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-matematika-un-sma"],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v27.5 - https:\/\/yoast.com\/product\/yoast-seo-wordpress\/ -->\n<title>Mau Siap Menghadapi UN Matematika? 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